提取两个相同定界符（多实例定界符）之间的行

Question

我想要的是从第一次出现定界符到最后一次出现相同定界符，包括它们之间的所有内容，定界符可能在日志文件中多次出现。 

sample.log

[T=iaaaaaaaaa134]:SampleClass9: 

[T=iaaaaaaaaa134]:SampleClass7: 

[T=iaaaaaaaaa134]:SampleClass3: 

[T=iaaaaaaaaa134]:SampleClass1: 

[T=i8732jddcd234]:SampleClass1: 

[T=i8732jddcd234]:SampleClass2: 

[T=i8732jddcd234]:SampleClass3: 

[T=i8732jddcd234]:SampleClass4: 

Exception:NullPointerException:

    sampte 1

    sampte 1

    sampte 1

    sampte 1

    sampte 1

    

[T=i8732jddcd234]:SampleClass00: 

[T=i8732jddcd234]:SampleClass00: 

[T=i8732jddcd234]:SampleClass00: 

[T=i8732jddcd234]:SampleClass00: 

[T=i8732jddcd234]:SampleClass00: 

Exception:NullPointerException2:

    sampte 2

    sampte 2

    sampte 2

    sampte 2

    sampte 2

[T=i8732jddcd234]:SampleClass12: 

[T=i8732jddcd234]:SampleClass32: 

[T=i8732jddcd234]:SampleClass22: 

[T=2eeeeeeeee234]:SampleClass32: 

[T=2eeeeeeeee234]:SampleClass82: 

[T=2eeeeeeeee234]:SampleClass22: 

[T=2eeeeeeeee234]:SampleClass22: 

例如：我想提取从第一次出现的i8732jddcd234（定界符）到最近一次出现的i8732jddcd234及其之间的所有行。可能使用awk，sed，grep linux命令。因为这是linux服务器上的日志文件。我尝试过

awk /'i8732jddcd234','i8732jddcd234'/ test.log

当然，这是行不通的

Answer 1

以下内容awk可能对您有所帮助。awk '/i8732jddcd234/{if(!first){first=FNR};end=FNR} {a[FNR]=$0} END{for(i=first;i<=end;i++){print a[i]}}'&nbsp; Input_file现在也添加非单一衬里形式的解决方案。awk '/i8732jddcd234/ {&nbsp; &nbsp;if (!first) {&nbsp; &nbsp; &nbsp; first = FNR&nbsp; &nbsp;}&nbsp; &nbsp;end = FNR}{&nbsp; &nbsp;a[FNR] = $0}END {&nbsp; for(i = first; i <= end; i++) {&nbsp; &nbsp; &nbsp;print a[i]&nbsp; }}'&nbsp; Input_file

Answer 2

last=$(nl sample.log | tac | awk '/i8732jddcd234/ {print $1; exit}')sed -n "/i8732jddcd234/,${last}p" sample.log或者，用awk进行2次遍历文件：awk -v code=i8732jddcd234 '&nbsp; &nbsp; NR == FNR {&nbsp; &nbsp; &nbsp; &nbsp; if ($0 ~ code) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; if (!first) first=FNR&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; last=FNR&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; next&nbsp; &nbsp; }&nbsp;&nbsp; &nbsp; first <= FNR && FNR <= last' sample.log sample.log

Answer 3

这可能对您有用（GNU sed）：sed&nbsp;'/i8732jddcd234/!d;:a;n;:b;//ba;$d;N;bb'&nbsp;file删除所有行，直到包含的行i8732jddcd234。打印包含的行i8732jddcd234，然后检查下一行是否也行，是否重复。否则，请收集行，直到下次出现i8732jddcd234或文件结束为止，在这种情况下，可以删除累积的行。