Python Day 10
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Leap Year
I have a friend Cindy, she was actually born on Feb.29th, and I remember we celebrated her birthday together 2012 in the Maths place!
Leap Year was adapted in Gregorian Calendar. There are Three Criteria:
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The year can be evenly divided by 4, is a leap year, unless:
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The year can be evenly divided by 100, it is NOT a leap year, unless:
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The year is also evenly divisible by 400. Then it is a leap year. [caption id=“attachment_1848” align=“alignnone” width=“750”]
pixel2013 / Pixabay[/caption]
Solution:
def is_leap(year):
if year % 4 != 0:
print("False")
elif year % 4 ==0 and year % 100==0 and year % 40==0:
print("Leap Year")
elif year % 4==0 and year % 100==0 and year % 40!=0 :
print("False")
else:
print("Leap Year")
Alternative Solutions:
#Alternative Solution
def is_leap1(year):
return year % 4 == 0 and (year % 400 == 0 or year % 100 != 0)
Output:
print(is_leap(1900))
False
2. Second Largest Number in a List
Suppose we want to find the Second Largest Number in a List
Ex: List=[4,6,3,2,2] Output=4
Solution:
arr=[2,5,4,2]
length=len(arr)
arr.sort()
print(arr[length-2])
3. Read an integer N, try to print out 123…N
EX: N=3, Output 123
Solution:
n= int(input())
print(*range(1,n+1), sep="")
n=8
1234567
Summary:
we have been working with the Python commands ***Range, Length, Sort, Module (%), and If-Then(elif-then, else), df***dAs all the books suggested, the Best way to learn to use the knowledge mindfully, so I organized this note :)
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