如何通过传递两个参数来修复方法调用函数

Question

我正在创建一个带有登录页面的待办事项列表，其中有一个两个输入表作为名称，名称中的事物，事物不向服务器发送数据

这是存储库...

public interface TodosRepository extends CrudRepository<Todos, Long> {

    Todos findByName(String name,String things);

    List<Todos> findByCompletedAndUserId(boolean complated, Long Id);

}

这是我的实体

@Entity

public class Todos {

    @Id

    @GeneratedValue(strategy = GenerationType.IDENTITY)

    private Long id;

    private String things;

    private String name;

    private boolean completed;

    @ManyToOne(fetch = FetchType.LAZY)

    @JoinColumn(name = "user_id")

    private User user;

    public Todos() {

    }

    public Todos(String name,String things, boolean completed) {

        this.things = things;

        this.name = name;

        this.completed = completed;

    }

    public String getThings() {

        return things;

    }

    public void setThings(String things) {

        this.things = things;

    }

    public Long getId() {

        return id;

    }

    public void setId(Long id) {

        this.id = id;

    }

    public String getName() {

        return name;

    }

    public void setName(String name) {

        this.name = name;

    }

    public boolean isCompleted() {

        return completed;

    }

    public void setCompleted(boolean completed) {

        this.completed = completed;

    }

    public User getUser() {

        return user;

    }

    public void setUser(User user) {

        this.user = user;

    }

    @Override

    public String toString() {

        return "Todos [id=" + id + ", name=" + name + ",things=" + things +", completed=" + completed + "]";

    }

}

java.util.NoSuchElementException：null

Answer 1

我认为拼写错误，这就是原因，completed而不是complated&nbsp;List<Todos> findByCompletedAndUserId(boolean complated, Long Id);&nbsp;参数名称应该与方法名称相同。就像方法名称有userId而参数只有id

Answer 2

你没有这个注释，请尝试使用下面的这一行@Entity@Table(name&nbsp;=&nbsp;"your-table")