行为步骤消歧/可选步骤参数

Question

我正在尝试支持以下功能场景：

Feature: test

  Scenario: Test optional

      Given attacked by samurai

        And attacked by samurai from behind

我的步骤文件是

from behave import step

@step('attacked by {opponent}')

def step_attacked_by(context, opponent):

    print(opponent)

@step('attacked by {opponent} from {direction}')

def step_attacked_by(context, opponent, direction):

    print(opponent)

    print(direction)

我收到错误：

behave.step_registry.AmbiguousStep: @step('attacked by {opponent} from {direction}') has already been defined in

  existing step @step('attacked by {opponent}') at steps/test.py:5

然后我尝试使用可选参数：

我的功能文件：

Feature: test

  Scenario: Test optional

      Given attacked by a samurai

我的步骤文件：

import parse

from behave import step, register_type

@parse.with_pattern(r"a\s+")

def parse_word_a(text):

    """Type converter for "a " (followed by one/more spaces)."""

    return text.strip()

register_type(a_=parse_word_a)

@step('attacked by {:a_?}{opponent}')

def step_attacked_by(context, a_, opponent):

    print(a_)

    print(opponent)

我收到此错误：

    raise ValueError('format spec %r not recognised' % type)

ValueError: format spec 'a_?' not recognised

我认为我真的不需要一个可选参数，只要我可以消除第一个示例中的步骤的歧义即可。

Answer 1

在使用 Behave 时，我注意到在步骤定义文件中定义步骤的顺序很重要。尝试首先从最具体的步骤开始定义您的步骤：@step('attacked by {opponent} from {direction}')def step_attacked_by(context, opponent, direction):    print(opponent)    print(direction)@step('attacked by {opponent}')def step_attacked_by(context, opponent):    print(opponent)运行你的 test.feature 不会再给我带来歧义错误。