if, elif & !=, == 布尔运算仅在输入时返回“false”

Question

我正在创建一个“我们之中”的盗版（为了好玩！），而 while True 和 if/elif/else 语句只会返回 false（不是冒名顶替者）的输入。我创建了一个姓名列表，列表中的 2 个随机元素将被选为An Impostor。但是，每当我输入The Impostor的名称时，它只会返回

（玩家）不是冒名顶替者。

这是我的代码；

import sys, time, random

names = ["player1", "player2", "player3", "player4", "player5", "player6", "player7", "player8", "player9", "player10"]

print("Players: ")

for x in names:

  print(x)

print('—————————————————————————')

impostor1 = random.choice(names)

impostor2 = random.choice(names)

crewmates = 8

impostors = 2

tries = 6

while True:

  talk = input("Guess who The Impostor(s) are. " + str(crewmates) + " Crewmates are left. " + str(impostors) + " Impostors are left. You have " + str(tries) + " tries left.")

  if talk in names:

    print(talk + " was voted for.")

    time.sleep(0.1)

    if talk != impostor1 or talk != impostor2:

      notimp = talk + " was not An Impostor. "

      names.remove(talk)

      for y in notimp:

        sys.stdout.write(y)

        sys.stdout.flush()

        time.sleep(0.05)

      crewmates -= 1

      tries -= 1

    elif talk == impostor1 or talk == impostor2:

      wasimp = talk + " was An Impostor. "

      names.remove(talk)

      for v in wasimp:

        sys.stdout.write(v)

        sys.stdout.flush()

        time.sleep(0.1)

      impostors -= 1

  else:

    print("That player was either ejected or is not a valid player.")

但是，每当我将冒名顶替者放入输入中时，它都会说它不是冒名顶替者？

Answer 1

我认为这一行是问题的根源：if talk != impostor1 or talk != impostor2:假设impostor1isplayer1 和impostor2isplayer2 以及inputplayer1中的某个人，根据PythonBoolean表达式运算符，or该if语句的计算结果如下：if player1 != impostor1评估为False因为player1 确实等于impostor1。到目前为止一切顺利，但由于第一个测试是False，Python 只是计算并返回右侧操作数，该操作数可能是True或False。在你的情况下，Python 将评估if talk != impostor2并返回True，然后执行嵌套块。