React redux useSelector 和参数

我试图理解为什么我似乎无法将参数传递给选择器。


本质上:我有一个存储数字和布尔值的逻辑 - 该数字是我想要选择材料元素的参数 - 我有一个调度操作的按钮:


//on a jobcard - dispatches to the material logic slice, pushing the number into the redux state: materialforJobNumber;

 <button className="materialViewer"  onClick={() =>{dispatch(materialView(data.jobsessionkey))}}> MATERIAL</button>


它分派到逻辑片:


//logic slice

materialView:(state, action)=>{

    console.log("what");

    console.log("material view succesfully called", action);

    const newState = {...state};

    console.log(newState);

    newState.materialforJobNumber = action.payload;

    newState.showMaterial=true;

    return newState

},

//the component that handles displaying the list of material for a job;


import {selectAttachedByJobKey} from "../MaterialCard/MaterialSlice";

const store= useStore();

const foundJN = store.getState().logic.materialforJobNumber;

const selectedJob=store.getState().jobs.find(x=>x.jobsessionkey==foundJN);

const materials = useSelector(selectAttachedByJobKey(foundJN));

const materialCards = materials.filter(x=>x.AttachedJobKey==foundJN).map((x,i)=><MaterialCard props={x} key ={i} />)



//material slice:

import { createSlice } from '@reduxjs/toolkit';


export const selectAttachedByJobKey = (state,action) =>{

    console.log("selecting material by job key",action);

    console.log(action?.payload);

    console.log(state);

    return state.material.filter(x=>x.AttachedJobkey===action?.payload);

}


我试图通过单击按钮来显示“工作”的相关材料。我正在使用 createReducer 函数模式,但我对如何实现这一点有点迷失 - 是否有更干净的方法来使用带有属性的选择器?


有只小跳蛙
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1回答

慕无忌1623718

useSelector仅接受一个函数state作为参数。如果你想传递其他变量,你可以使用柯里化方法:export const selectAttachedByJobKey = (action) => (state) =>{&nbsp; &nbsp; console.log("selecting material by job key",action);&nbsp; &nbsp; console.log(action?.payload);&nbsp; &nbsp; console.log(state);&nbsp; &nbsp; return state.material.filter(x=>x.AttachedJobkey===action?.payload);}现在,当您这样做时,const materials = useSelector(selectAttachedByJobKey(foundJN));您将传递给可用的useSelector函数foundJN。
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