我正在更新一个项目,以明确了解客户,以前假设客户,因为我们只有一个......
我的问题是向 HQL 查询添加 where 子句。
我的出发点是这个查询:
public static final String SELECT_DISTINCT_STORES =
"select DISTINCT e.storeNum, e.city, e.state from BoEngagement e order by e.storeNum";
我想添加一个where e.customer_fk = :customer_fk子句,但每次添加 where 子句时,我都会收到各种org.hibernate.hql.internal.ast.QuerySyntaxException错误,除非我取出distinct关键字,但我不相信查询会给出我所期望的结果。
这有效:
"select e.storeNum, e.city, e.state from BoEngagement e WHERE e.customer_fk = :customer_fk";
而且,如果我要简化查询那么多,它确实应该是
"select e from BoEngagement e WHERE e.customer_fk = :customer_fk";
然而,正如我所说,我不相信删除关键字distinct是我想要做的。
以下是我尝试过的一些事情:
"select DISTINCT e.storeNum, e.city, e.state FROM BoEngagement e WHERE e.customer_fk = :customer_fk order by e.storeNum";
给出这个错误
[ERROR] 2019-10-18 15:10:03.449 [main] BsRetrieveDistinct - java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: FROM near line 1, column 94 [SELECT DISTINCT e.city, e.state from com.bh.radar.bo.BoEngagement e order by e.state, e.city FROM com.bh.radar.bo.BoEngagement e WHERE e.customer_fk = :customer_fk]
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: FROM near line 1, column 94 [SELECT DISTINCT e.city, e.state from com.bh.radar.bo.BoEngagement e order by e.state, e.city FROM com.bh.radar.bo.BoEngagement e WHERE e.customer_fk = :customer_fk]
这个更复杂的版本
"select DISTINCT e.storeNum, e.city, e.state FROM BoEngagement e in " +
"(select g FROM BoEngagement g WHERE g.customer_fk = :customer_fk order by g.storeNum)";
显然我并没有完全理解HQL和distinct关键字。我究竟做错了什么?
一只名叫tom的猫
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