PHP - 将 16 位数字模式映射到二进制块

Question

我正在开发一个用于鼓声音的步进音序器程序。它采用 16 位二进制模式示例："1010010100101001"，然后将二进制模式分解为如下所示的块：10, 100, 10, 100, 10, 100, 1。然后，它根据有多少个块为每个块分配一个时间值。数字。原因是有些鼓样本声音发出的声音比 1 节拍的长度长，所以分块解决了这部分。（例如，如果节拍为 60bpm 1 位 = 1 秒）“10”= 2 秒，“100”= 3 秒，“1”= 秒。（允许我在模式中将声音修剪到适当的长度，并使用 ffmpeg 将其连接成最终的 wav）另外 1 = 鼓击 / 0 = 无声击......这种方法非常适合我的需要。

现在我可以制作完美的节拍循环......并且我想在其之上添加速度模式层，以允许幽灵音符/为我的鼓模式添加人的感觉/动态。我决定对速度模式使用 0、1、2、3、4 值系统。“0”= 0% 体积，“1”= 25% 体积，“2”= 50% 体积，“3”= "0"= 0% 体积，"1"= 25% 体积，"2"= 50% 体积，"3"= 75% 体积，"4"= %100 体积。（音量为 0，这样我就可以添加打开踩镲/铙钹碰撞硬停止，而二进制模式中的 0 则不会这样做）因此，除了"1111111111111111"模式外，您还会看到一个速度模式层，例如"4242424242424242"（该速度模式交替使用 100% 击打和 50% 击打，使用踩镲听起来不错/就像真正的鼓手）

我使用 PHP 将 16 位二进制模式分解为一个块数组。"1001110011110010"将是

['100','1','1','100','1','1','1','100','10']

现在通过循环，我需要将 0、1、2、3、4 位数字的另一个 16 位数字层模式映射到每个块的第一位数字。

示例1：

Velocity Pattern: '4242424242424242'

Binary Pattern: '1001110011110010'

Array = ['100','1','1','100','1','1','1','100','10']

'100' = 4 (1st digit in 4242424242424242 pattern)

'1' = 2 (4th digit in 4242424242424242 pattern)

'1' = 4 (5th digit in 4242424242424242 pattern)

'100' = 2 (6th digit in the 4242424242424242 pattern)

'1' = 4 (9th digit in the 4242424242424242 pattern)

'1' = 2 (10th digit in the 4242424242424242 pattern)

'1' = 4 (11th digit in the 4242424242424242 pattern)

'100' = 2 (12th digit in the 4242424242424242 pattern)

'10' = 4 (15th digit in the 4242424242424242 pattern)

示例2：

Velocity Pattern: '4242424242424242'

Binary Pattern: '1111111111111111'

Array = ['1','1','1','1','1','1','1','1','1','1','1','1','1','1','1','1']

Answer 1

从您给出的示例来看，您似乎需要速度数组中的相应值以及节拍数组中 1 之间的持续时间。此代码首先通过将 1 拆分为数组，然后过滤掉 0 来提取 1。所以$beat_pattern = '1001110011110010';$velocity_pattern = '4242424242424242';$beat = array_filter(str_split($beat_pattern));会屈服......$beatArray(&nbsp; &nbsp; [0] => 1&nbsp; &nbsp; [3] => 1&nbsp; &nbsp; [4] => 1&nbsp; &nbsp; [5] => 1&nbsp; &nbsp; [8] => 1&nbsp; &nbsp; [9] => 1&nbsp; &nbsp; [10] => 1&nbsp; &nbsp; [11] => 1&nbsp; &nbsp; [14] => 1)然后它依次获取每个条目，通过查看下一个键并减去两个键来计算长度，还使用索引来获得相应的速度。要考虑以 0 开头的情况，您可以循环到 1 的第一个实例并输出同一元素的速度模式......$beat_pattern = '1001110011110010';$velocity_pattern = '4242424242424242';$beat = array_filter(str_split($beat_pattern));$beatKeys = array_keys($beat);// For the leading 0'sfor( $i = 0; $i < $beatKeys[0]; $i++ )&nbsp; {&nbsp; &nbsp; echo "1-". $velocity_pattern[$i] . PHP_EOL;}for ( $i = 0; $i < count($beatKeys); $i++ ) {&nbsp; &nbsp; echo ($beatKeys[$i+1] ?? strlen($beat_pattern)) - $beatKeys[$i] . "-".&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; $velocity_pattern[$beatKeys[$i]] . PHP_EOL;}给出（长度-速度）...3-41-21-43-21-41-21-43-22-4

Answer 2

假设您有两个输入字符串：$binary&nbsp; &nbsp;= '0001000110101001';$velocity = '4231423142314231';如果使用正则表达式分析模式，则可以在一次操作中获取所有组成部分，包括模式开始时的停顿（基本上是 0% 的音量节拍）。$index = 0;preg_match_all('/^0+|10*/', $binary, $parts);foreach ($parts[0] as $part) {&nbsp; &nbsp; $duration = strlen($part);&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;// How many beats&nbsp; &nbsp; $volume = $part[0] ? $velocity[$index] : 0;&nbsp; // The corresponding volume number&nbsp; &nbsp; $index += $duration;}为了进一步发展这一点，在我看来，为模式生成适当的数据数组是可行的，如果你愿意，你可以打包这个功能：function drumPattern($binary, $velocity) {&nbsp; &nbsp; $output = [];&nbsp; &nbsp; $index = 0;&nbsp; &nbsp; preg_match_all('/^0+|10*/', $binary, $parts);&nbsp; &nbsp; foreach ($parts[0] as $part) {&nbsp; &nbsp; &nbsp; &nbsp; $duration = strlen($part);&nbsp; &nbsp; &nbsp; &nbsp; $output[] = [&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 'duration' => $duration,&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; 'volume' => $part[0] ? $velocity[$index] : 0&nbsp; &nbsp; &nbsp; &nbsp; ];&nbsp; &nbsp; &nbsp; &nbsp; $index += $duration;&nbsp; &nbsp; }&nbsp; &nbsp; return $output;}例drumPattern($binary, $velocity);生成以下输出Array(&nbsp; &nbsp; [0] => Array&nbsp; &nbsp; &nbsp; &nbsp; (&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [duration] => 3&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [volume] => 0&nbsp; &nbsp; &nbsp; &nbsp; )&nbsp; &nbsp; [1] => Array&nbsp; &nbsp; &nbsp; &nbsp; (&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [duration] => 4&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [volume] => 1&nbsp; &nbsp; &nbsp; &nbsp; )&nbsp; &nbsp; [2] => Array&nbsp; &nbsp; &nbsp; &nbsp; (&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [duration] => 1&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [volume] => 1&nbsp; &nbsp; &nbsp; &nbsp; )&nbsp; &nbsp; [3] => Array&nbsp; &nbsp; &nbsp; &nbsp; (&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [duration] => 2&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [volume] => 4&nbsp; &nbsp; &nbsp; &nbsp; )&nbsp; &nbsp; [4] => Array&nbsp; &nbsp; &nbsp; &nbsp; (&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [duration] => 2&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [volume] => 3&nbsp; &nbsp; &nbsp; &nbsp; )&nbsp; &nbsp; [5] => Array&nbsp; &nbsp; &nbsp; &nbsp; (&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [duration] => 3&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [volume] => 4&nbsp; &nbsp; &nbsp; &nbsp; )&nbsp; &nbsp; [6] => Array&nbsp; &nbsp; &nbsp; &nbsp; (&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [duration] => 1&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; [volume] => 1&nbsp; &nbsp; &nbsp; &nbsp; ))