多维数组使用数组中找到的数值从高到低排序
我目前正在寻找一种有效的方法来根据最高 -> 最低使用对数组/对象进行排序avgTotalPoints，然后根据字段中的排名放置数值rank。我查看了一些示例并能够相应地创建一个函数。然而，它现在正在发挥作用。我试图访问avgTotalPoints下面所示的排序函数，但我无法访问，因为数组是多深度的。关于如何实现这一目标有任何指导吗？
function sortHighestToLowest($arr)
{
if (isset($arr) && !empty($arr)) {
uasort($arr, function ($a, $b) {
return $a['avgTotalPoints'] <=> $b['avgTotalPoints'];
});
return array_reverse($arr);
}
return null;
}
JSON 输入
{
"mlb": {
"james": {
"avgTotalPoints": 80.675,
"avgPointsDifferential": -0.8112500000000002,
"rank": null
},
"mary": {
"avgTotalPoints": 114.9875,
"avgPointsDifferential": 6.262500000000003,
"rank": null
},
"lucas": {
"avgTotalPoints": 66.825,
"avgPointsDifferential": -9.10625,
"rank": null
},
"timothy": {
"avgTotalPoints": 69.2625,
"avgPointsDifferential": -19.14125,
"rank": null
},
"samantha": {
"avgTotalPoints": 91.625,
"avgPointsDifferential": -36.85000000000001,
"rank": null
}
},
"nhl": {
"samantha": {
"avgTotalPoints": 82.20000000000002,
"avgPointsDifferential": 15.005714285714289,
"rank": null
},
"peter": {
"avgTotalPoints": 77.65714285714284,
"avgPointsDifferential": -13.31857142857143,
"rank": null
},
"rick": {
"avgTotalPoints": 91.61428571428571,
"avgPointsDifferential": 11.217142857142859,
"rank": null
},
"bubba": {
"avgTotalPoints": 119.60000000000001,
"avgPointsDifferential": 28.13333333333334,
"rank": null
},
"james": {
"avgTotalPoints": 90.18571428571428,
"avgPointsDifferential": 10.915714285714285,
"rank": null
}
}
}
慕运维80795931回答
-
鸿蒙传说
由于您的数组包含多个要单独排序的子数组，因此您可以利用将array_map排序应用于每个子数组。执行此操作后，您可以简单地循环遍历同一子数组（通过引用）$rank，同时递增变量并将其分配给每个条目。另外，您不需要使用array_reverse反转排序，只需反转<=>比较的操作数即可。function sortHighestToLowest(array $arr): array{ return array_map(static function (array $entries): array { uasort($entries, static function (array $entry1, array $entry2): int { return $entry2['avgTotalPoints'] <=> $entry1['avgTotalPoints']; }); $rank = 0; foreach ($entries as &$entry) { $entry['rank'] = ++$rank; } return $entries; }, $arr);}演示
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