如何将常量数组与用户输入数组相乘？

4回答

一只斗牛犬

尝试使用const input = '837465'.split('')或准备好数组const input = [8, 3, 7, 4, 6, 5]和reduce()方法来求和数组。当原始数组中有元素时，reduce 就会起作用const array = [5, 7, 3, 5, 2]const input = '837465'.split('')//or // const input = [8, 3, 7, 4, 6, 5]const summ = (input) => array.reduce((acum, rec, index) => acum + (rec * input[index]), 0)console.log(summ(input))

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Helenr

for您可以使用清晰的语法of强制执行此操作const arr = [5, 7, 3, 5, 2]const nums = [8, 3, 7, 4, 6, 5]let result = 0for (const [ key, value ] of Object.entries(arr))  result = result + (value * nums[key])console.log(result) // 114或者您可以使用声明式地执行此操作Array.prototype.reduce-const arr = [5, 7, 3, 5, 2]const nums = [8, 3, 7, 4, 6, 5]const result =  arr.reduce    ( (sum, value, key) => sum + (value * nums[key])    , 0    )console.log(result) // 114

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jeck猫

这是答案（请点击“运行代码片段”）如果您需要任何解释，或者这不是您要问的，请评论我的答案function getTotal() {  const arr = [5, 7, 3, 5, 2];  var userNumbers = document.getElementById('yourNumber').value.split('');   var sum = 0;  //itreate over your array case it is short (or a condition to itreate over the shortest one)  for (var i = 0; i < arr.length; i++) {    sum += parseInt(userNumbers[i]) * arr[i];  }  console.log(sum);  document.getElementById('answer').innerHTML ='Answer will be here: '+ sum;}<html><head>  <title>StackOverFlow 🍗</title>  <link rel="shortcut icon" type="image/x-icon" href="https://image.flaticon.com/icons/png/512/2057/2057586.png" /></head><body>  <h3>Stack Over Flow 🍗</h3>  <input id="yourNumber" type="text" value="837465">  <button onclick="getTotal()">get the answer</button>    <p id="answer">Answer will be here: </p></body></html>

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慕村9548890

以下作品：const arr = [5, 7, 3, 5, 2];var num = document.getElementById("yourNumber").value; //input from .htmlvar sum = 0;for (var i = 0; i< num.length-1; i++){  //var i = 1 b/c user always enters 6 digits, i feel this is wrong?    sum += (arr[i]*parseInt(num[i]));}console.log(sum);

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