值错误和零除错误

Question

我正在尝试执行计算 ((x/y) + z) 并解释 2 个错误：ValueError和ZeroDivisionError.

但是，我很难理解如何将这两个错误编码到我的程序中。我想我已经ValueError明白了，但还没有ZeroDivisionError。这是我到目前为止所拥有的。抱歉，有点乱 rn....

user_input = (input("Enter three numbers separated by a space: ")).split()

x = int(user_input[0])

y = int(user_input[1])

z = int(user_input[2])

  

def calculate(x, y, z):

    '''calculate (x/y)+z'''

    c = ((x/y) + z) if y != 0 else print("Second input value cannot be 0")

    return c

try:

    input_values_str = str(user_input)

    c = ((x/y) + z)

    for val in input_values_str:

        if len(user_input) == 3:

            print("Correct number of values.")

        else:

            print("Incorrect number of values entered.")

except ValueError:

    print(user_input," is not valid input.")

except ZeroDivisionError:

    y = 0

    print("Second value cannot be 0")

print("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z)))

Answer 1

恭喜你学习了Python！我认为你的代码有点混乱。我将发布您的版本以及我的一些评论，然后我将发布一个清理版本，我认为它可以更好地实现您想要做的事情。希望它具有指导意义。有更优雅的方法可以做到这一点，但我试图保留你的结构尽可能有意义。您的代码：user_input = (input("Enter three numbers separated by a space: ")).split()x = int(user_input[0])y = int(user_input[1])z = int(user_input[2])def calculate(x, y, z):    c = ((x/y) + z) if y != 0 else print("Second input value cannot be 0")  #Why do you need a ZeroDivisonError check below when you check for Zero here?return ctry:    input_values_str = str(user_input) # why are you taking an input here? Did you take the input above? And why convert it back into a string?    c = ((x/y) + z)    for val in input_values_str: # Why are you iterating through string? You're basically checking 3 times if the length of your string is 3 characters        if len(user_input) == 3:            print("Correct number of values.")        else:            print("Incorrect number of values entered.")except ValueError:    print(user_input," is not valid input.")except ZeroDivisionError:    y = 0 # why set y back to zero in the event oa ZeroDivisonError? Won't that just create a ZeroDivison Error? Might make more sense to get a new input from the user    print("Second value cannot be 0")print("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z))) # if the objective is to only print something, why not do it in the calculate function? Then we can contain your ZeroDivisionError in their and request a new y我的代码：def calculate(x, y, z):    try:        solution = (x/y) + z        print(f"Formula: ({x}/{y}) + {z} = {solution}")    except ZeroDivisionError:        y = int(input("2nd value cannot be a Zero. Please input a new y value: "))        calculate(x, y, z)try:    user_input = (input("Enter three numbers separated by a space: ")).split()    while len(user_input) != 3:        print("Incorrect number of values entered.")        user_input = (input("Enter three numbers separated by a space: ")).split()    x = int(user_input[0])    y = int(user_input[1])    z = int(user_input[2])    calculate(x, y, z)except ValueError:    print(user_input," is not valid input.")

Answer 2

我只是调整了您的代码以满足您的期望，并且易于理解。user_input = (input("Enter three numbers separated by a space: ")).split()x = int(user_input[0])y = int(user_input[1])z = int(user_input[2])try:    c = ((x/y) + z) if y != 0 else print("Second input value cannot be 0")except ValueError:    print(user_input," is not valid input.")print("Formula: ({}/{}) + {} = {}".format(x, y, z, c))

Answer 3

我根本不明白为什么你需要 try/ except/ except 块。y=0您已经在您的方法中进行了检查calculate，并且您已经知道您有有效的输入，否则 和split强制转换int()将会失败。其中的循环for一遍又一遍地打印相同的输出字符串。如果你把所有这些都去掉，你的代码似乎工作正常try:    file_name = open('/tmp/data.txt', 'r')except FileNotFoundError:    print("File could not be found. Please check spelling of file name!")    sys.exit()#Read lines in fileLines = file_name.read().splitlines()user_input = (input("Enter three numbers separated by a space: ")).split()x = int(user_input[0])y = int(user_input[1])z = int(user_input[2])def calculate(x, y, z):    '''calculate (x/y)+z'''    c = ((x / y) + z) if y != 0 else print("Second input value cannot be 0")    return cprint("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z)))

Answer 4

您引发了一个异常来查看 y == 0 是否，但第一个值 (x) 也不能为 0。并且您需要将 2 个 if 语句放在 c = ... 之前尝试这个：user_input = (input("Enter three numbers separated by a space: ")).split()x = int(user_input[0])y = int(user_input[1])z = int(user_input[2])def calculate(x, y, z):    '''calculate (x/y)+z'''    if y == 0 or x == y:        print("Invalid Input")    else:        c = ((x/y) + z)        return ctry:    input_values_str = str(user_input)    c = ((x/y) + z)    for val in input_values_str:        if len(user_input) == 3:            print("Correct number of values.")        else:            print("Incorrect number of values entered.")except ValueError:    print(user_input," is not valid input.")except ZeroDivisionError:    y = 0    x = 0    print("Second value cannot be 0. First Value cannot be 0")    print("Formula: ({}/{}) + {} = {}".format(x, y, z, calculate(x, y, z)))