查找列表组的金额总和

5回答

富国沪深

使用Array.reduce()var sample= [   {  Name: 'Poorna', Amount: 50},   {  Name: 'Kumar', Amount: 50},   {  Name: 'Ashok ', Amount: 75},   {  Name: 'Poorna', Amount: 35},   ];var res = sample.reduce((a, obj)=>{  var existItem = a.find(item => item.Name=== obj.Name);  if(existItem){    existItem.Amount += obj.Amount;    return a;  }   a.push(obj);  return a;}, []);console.log(res);

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慕码人2483693

您可以使用地图来做到这一点：import React from "react";export default function App() {  const list = [    { name: 'Poorna', amount: 11000 },    { name: 'Kumar', amount: 2900 },    { name: 'Ashok', amount: 20000 },    { name: 'Kumar', amount: 3020 },    { name: 'Poorna', amount: 15000 }  ];  const map = new Map();  list.forEach(({ name, amount }) =>          map.set(name, map.has(name) ? map.get(name) + amount : amount));  const listItems = [...map.entries()].map(([name, amount]) => <li>{name}: {amount}</li>);  return <ul>{listItems}</ul>;}

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繁星淼淼

我认为下面是最好的方法。const data = [   {  Name: 'Poorna', Amount: 11000 },   {  Name: 'Kumar', Amount: 2900 },   {  Name: 'Ashok', Amount: 20000 },   {  Name: 'Kumar', Amount: 3020 },   {  Name: 'Poorna', Amount: 15000 },];const result = data.reduce((prev, { Name, Amount }) => {  if (prev[Name]) return {...prev, [Name]: prev[Name] + Amount};  return {...prev, [Name]: Amount};}, {});

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慕桂英546537

这是根据名称对数据进行分组的方法：let data = [  {name: "Poorna", salary:11000.0},  {name: "Kumar",salary: 2900.0},  {name: "Ashok", salary:20000.0},  {name: "Kumar", salary:3020.0},  {name: "Poorna", salary:15000.0},];let sol = {};for (let a of data) {  if (sol[a.name]) {sol[a.name] += a.salary;  } else {sol[a.name] = a.salary;  }}console.log(sol);这是完整的反应应用程序：import React, { useState, useEffect } from "react";import "./style.css";let data = [  { name: "Poorna", salary: 11000.0 },  { name: "Kumar", salary: 2900.0 },  { name: "Ashok", salary: 20000.0 },  { name: "Kumar", salary: 3020.0 },  { name: "Poorna", salary: 15000.0 }];export default function App() {  const [initialData, setInitialData] = useState(data);  const [group, setGroup] = useState([]);  const groupData = () => {    let sol = {};    for (let a of initialData) {      if (sol[a.name]) {        sol[a.name] += a.salary;      } else {        sol[a.name] = a.salary;      }    }    setGroup(sol);  };  useEffect(() => {    groupData();  }, []);  return (    <div>      <table>        <tr>          {" "}          <th>Name</th>          <th>Amount</th>        </tr>        {initialData.map(d => (          <tr>            {" "}            <td>{d.name}</td>            <td>{d.salary}</td>          </tr>        ))}      </table>      <h2>Grouped data</h2>      <table>        <tr>          <th>Name</th>          <th>Amount</th>        </tr>        {group &&          Object.keys(group).map(key => (            <tr>              <td>{key}</td>              <td>{group[key]}</td>            </tr>          ))}      </table>    </div>  );}您可以在这里找到工作应用程序：Stackblitz Link

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九州编程

使用reduce()const array = [{ id: 1, name: 'Poorna', amount: 11000 }, { id: 2, name: 'Kumar', amount: 2900}, { id: 3,  name: 'Ashok', amount: 20000},{ id: 3,  name: 'Kumar', amount: 3020},{ id: 3,  name: 'Poorna', amount: 15000}];     let output = Object.values(array.reduce((acc, curr) => {     if (acc[curr.name]) acc[curr.name].amount += curr.amount;     else acc[curr.name] = { ...curr };     return acc;    }, {}));console.log(output);

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