PHP、XML 元素路径

Question

嘿，我正在尝试从 XML 文件中获取查看者。问题出在路径上，因为其他路径对我有用。我想问题是因为它是元素？<media:statistics views="131"/>

$url = "https://www.youtube.com/feeds/videos.xml?channel_id=UCH7Hj6l_xDmbyvjQOA5Du0g";

$xml = simplexml_load_file($url);

$views = $xml->entry[0]->children('media', true)->group[0]->children('media', true)->community[0]->children('media', true)->attributes('statistics');

echo $views;

Answer 1

您可以通过使用而不是首先使用统计属性来获取视图->attributes('statistics')，然后从属性中获取视图：->statistics->attributes()->views;代码可能如下所示：$url = "https://www.youtube.com/feeds/videos.xml?channel_id=UCH7Hj6l_xDmbyvjQOA5Du0g";$xml = simplexml_load_file($url);$views = $xml->entry[0]->children('media', true)->group[0]->children('media', true)->community[0]->children('media', true)->statistics->attributes()->views;echo $views;输出131