JsonConvert 将十进制反序列化为 jtoken 将其转换为科学数字

我有一个带有对象属性的类,如果我使用该属性的十进制值创建该类并序列化它,该值看起来很好:


var testObject = new TestObject{

    TestDecimal = 8801203167395152041.7m

};

var serialized = Newtonsoft.Json.JsonConvert.SerializeObject(testObject);

serialized.Dump(); // returns {"TestDecimal":8801203167395152041.7}

但是,如果我尝试使用 jtoken 反序列化该值,该值将变为科学值并保存为双精度值,以下是整个代码:


void Main()

{


    var testObject = new TestObject{

        TestDecimal = 8801203167395152041.7m

    };

    var serialized = Newtonsoft.Json.JsonConvert.SerializeObject(testObject);


    serialized.Dump();

    TestObject result = JsonConvert.DeserializeObject<TestObject>(serialized, new JsonSerializerSettings

    {

        Converters = new List<JsonConverter> { new TestDesiralizer() }

    });

    testObject.TestDecimal.Dump();

    result.TestDecimal.Dump();


}


public class TestObject{

    public object TestDecimal { get; set; }

}


public class TestDesiralizer : JsonConverter

{

    public override bool CanConvert(Type objectType)

    {

        return objectType == typeof(TestObject);

    }


    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)

    {

        serializer.Culture = CultureInfo.InvariantCulture;

        reader.Culture = CultureInfo.InvariantCulture;

        JToken token = serializer.Deserialize<JToken>(reader);

        TestObject obj = token.ToObject<TestObject>();

        obj.TestDecimal =  decimal.Parse(Convert.ToString(obj.TestDecimal,CultureInfo.InvariantCulture) ?? "",NumberStyles.Any, CultureInfo.InvariantCulture);

        return obj;

    }


    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)

    {

        throw new NotImplementedException();

    }

}

这导致:


1) 8801203167395152041,7


2) 8801203167395150000


反序列化json时如何保留十进制值?


偶然的你
浏览 77回答 1
1回答

DIEA

在反序列化期间设置以下内容似乎可以解决该问题:reader.FloatParseHandling = FloatParseHandling.Decimal
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