将数据插入到 2 个独立的 mySQL 表中
下面是我正在尝试做的事情的简化版本。本质上我有 2 个注册表，每个表单的内容都将写入不同的表。当我加载表单时，我在第 xx 行上收到许多错误未定义索引，并且在本示例的第 75 行和第 84 行中仍然收到错误，我认为错误归结于某些“必需”字段，但该页面尚未加载为它使用一些 JS 就飘走了。... 请帮忙！
<?php
ob_start(); //Turns on output buffering
session_start(); //This starts a session variable where it store the input so the user doesnt have to start over if they get an error
$con = mysqli_connect("localhost","root","","test-sql"); //connection variables
$timezone = date_default_timezone_set("Europe/London");
if(mysqli_connect_errno()){
echo "failed to connect:" . mysqli_connect_errno();
}
?>
<html>
<head>
<! here we add the links and the jquery>
<title>Register Project</title>
</head>
<body>
<div id="first">
<form action="test-sql.php" method="POST">
<input type="text" name="Inf_fname" placeholder="First Name" required>
<br>
<input type="text" name="Inf_lname" placeholder="Last Name" required>
</form>
</div>
<div id="second">
<form action="test-sql.php" method="POST">
<br>
<input type="text" name="Cust_fname" placeholder="First Name" required>
<br>
<input type="text" name="Cust_lname" placeholder="Last Name" required>
<br>
<input type="submit" name="register_button" value="Register">
</form>
</div>
</body>
</html>
<?php
$inf_fname = "";
$cust_fname = "";
$inf_lname = "";
$cust_lname = "";
if(isset($_POST['register_button'])) {
$inf_fname = strip_tags($_POST['Inf_fname']);
$inf_fname = str_replace(' ', '', $inf_fname);
$_SESSION['Inf_fname'] = $inf_fname;
}
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-
慕码人8056858
由于您一次仅提交一种格式，因此无法插入到两个表中。您需要检查提交的是哪个表单，并插入到相应的表中。每个表单都需要一个具有不同名称或值的提交按钮，这样您就可以知道在 PHP 中使用了哪一个。您还应该使用准备好的语句，而不是将变量替换到 SQL 中，以防止 SQL 注入。我已经展示了如何做到这一点。<?phpob_start(); //Turns on output bufferingsession_start(); //This starts a session variable where it store the input so the user doesnt have to start over if they get an error$con = mysqli_connect("localhost","root","","test-sql"); //connection variables $timezone = date_default_timezone_set("Europe/London"); if(mysqli_connect_errno()){ echo "failed to connect:" . mysqli_connect_errno();}?><html><head><! here we add the links and the jquery><title>Register Project</title></head><body> <div id="first"> <form action="test-sql.php" method="POST"> <input type="text" name="Inf_fname" placeholder="First Name" required> <br> <input type="text" name="Inf_lname" placeholder="Last Name" required> <input type="submit" name="inf_submit" value="Register"> </form></div><div id="second"> <form action="test-sql.php" method="POST"> <br> <input type="text" name="Cust_fname" placeholder="First Name" required> <br> <input type="text" name="Cust_lname" placeholder="Last Name" required> <br> <input type="submit" name="cust_submit" value="Register"> </form></div></body></html> <?php $inf_fname = ""; $cust_fname = ""; $inf_lname = ""; $cust_lname = ""; if(isset($_POST['inf_submit'])) { $inf_fname = strip_tags($_POST['Inf_fname']); $inf_fname = str_replace(' ', '', $inf_fname); $_SESSION['Inf_fname'] = $inf_fname; $inf_lname = strip_tags($_POST['Inf_lname']); $inf_lname = str_replace(' ', '', $inf_lname); $_SESSION['Inf_lname'] = $inf_lname; $stmt = mysqli_prepare($con, "INSERT INTO inf VALUES (?, ?)"); mysqli_stmt_bind_param($stmt, "ss", $inf_fname, $inf_lname); mysqli_stmt_execute($stmt); } elseif (isset($_POST['cust_submit'])) { $cust_fname = strip_tags($_POST['Cust_fname']); $cust_fname = str_replace(' ', '', $cust_fname); $_SESSION['Cust_fname'] = $cust_fname; $cust_lname = strip_tags($_POST['Cust_lname']); $cust_lname = str_replace(' ', '', $cust_lname); $_SESSION['Cust_lname'] = $cust_lname; $stmt = mysqli_prepare($con, "INSERT INTO customer VALUES (?, ?)"); mysqli_stmt_bind_param($stmt, "ss", $cust_fname, $cust_lname); mysqli_stmt_execute($stmt); } ?>
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