字符串数组中每个元素的平均长度

Question

我试图获取字符串数组中每个元素的平均长度。但不确定我的代码。有什么建议么？

public static double averageLength(String[] words, int count) {

        double countedLength = 0.0;

        for(int i = 0; i < words.length; i++) {

            countedLength += words[i].length();

            count++;

        }

        return (double)countedLength / count;

    }

Answer 1

您还可以使用 Stream API 来执行此任务：public&nbsp;static&nbsp;double&nbsp;averageLength(String[]&nbsp;words)&nbsp;{ &nbsp;&nbsp;&nbsp;&nbsp;return&nbsp;Arrays.stream(words) &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;.mapToDouble(String::length) &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;.average() &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;.getAsDouble(); }

Answer 2

更改返回至&nbsp;return&nbsp;(double)countedLength&nbsp;/&nbsp;words.length;

Answer 3

求平均值时，您需要除以求和的元素数量。此外，在您的方法中，您不需要传递count变量，因为您的方法中未使用它。public static double averageLength(String[] words) {&nbsp; double countedLength = 0.0;&nbsp; for(int i = 0; i < words.length; i++) {&nbsp; &nbsp; countedLength += words[i].length();&nbsp; }&nbsp; return countedLength / words.length;}出于兴趣，您也可以始终使用foreach循环结构来迭代元素：public static double averageLength(String[] words) {&nbsp; int countedLength = 0;&nbsp; for(String word : words) {&nbsp; &nbsp; countedLength += word.length();&nbsp; }&nbsp; return countedLength / words.length;}然而结果是一样的。