所以,我尝试使用 openpyxl 用这一行打开一个 excel 文件
wb_bs = openpyxl.load_workbook(filename=filepath)
并得到这个错误:
C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\styles\stylesheet.py:214: UserWarning: Workbook contains no default style, apply openpyxl's default
warn("Workbook contains no default style, apply openpyxl's default")
Traceback (most recent call last):
wb_bs = openpyxl.load_workbook(filename=url_nova, data_only=True)
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\reader\excel.py", line 315, in load_workbook
reader.read()
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\reader\excel.py", line 280, in read
self.read_worksheets()
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\reader\excel.py", line 228, in read_worksheets
ws_parser.bind_all()
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\worksheet\_reader.py", line 434, in bind_all
self.bind_cells()
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\worksheet\_reader.py", line 337, in bind_cells
for idx, row in self.parser.parse():
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\worksheet\_reader.py", line 149, in parse
obj = prop[1].from_tree(element)
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\descriptors\serialisable.py", line 87, in from_tree
obj = desc.expected_type.from_tree(el)
File "C:\Users\T-Gamer\AppData\Local\Programs\Python\Python38-32\lib\site-packages\openpyxl\descriptors\serialisable.py", line 103, in from_tree
return cls(**attrib)
事情是:
如果我创建 .xlsx 文件,它将打开
如果我从这个特定来源(我需要的来源)下载文件并尝试立即打开它,则会生成错误。
如果我在打开并保存 .xlsx 文件(无更改)后运行代码,它就会起作用。
我想这与Excel版本冲突有关,但我已经尝试了所有方法,但似乎没有任何效果。
openpyxl==3.0.5 python==3.8.5
大话西游666
慕桂英4014372
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