是否可以将 PHP 查询变量传递给 JS，而不在查看源代码中显示它？
我正在尝试创建一个从 MySQL 数据库读取提示的系统，并在适当的时间向用户显示它们。然而，当在网页上查看时，我还没有设法获得VARCHAR要显示的 JS 变量的提示 ( )，而不将它们暴露在 HTML 中。这是我的代码：
<?php
require_once ('config.php'); <!-- This connects to the database, all details are in the config.php -->
$result = $link->query ('SELECT `hint1`, `hint2`, `hint3`, `hint4`, `hint5`, `hint6`, `hint7` FROM `hints` WHERE `questNo` = 1');
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
$hint1 = $row['hint1'];
$hint2 = $row['hint2'];
$hint3 = $row['hint3'];
$hint4 = $row['hint4'];
$hint5 = $row['hint5'];
$hint6 = $row['hint6'];
$hint7 = $row['hint7'];
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Help</title>
</head>
<body>
<!-- Start Hell -->
<div id="dom-target" style="display: none;">
<?php
echo htmlspecialchars($hint1);
?>
</div>
<script>
var div = document.getElementById("dom-target");
var hint1 = div.textContent;
</script>
(This would be repeated for all hints)
--------------------------------
(UNIMPORTANT HTML)
--------------------------------
<h2 style="text-decoration: underline;"> Hints<br></h2>
<br>
<h2 onclick="displayHint()" id="hint1">Click for hint</h2>
<br>
<h2 onclick="displayHint()" id="hint2">Click for hint</h2>
<br>
<h2 onclick="displayHint()" id="hint3">Click for hint</h2>
<br>
<h2 onclick="displayHint()" id="hint4">Click for hint</h2>
<br>
<h2 onclick="displayHint()" id="hint5">Click for hint</h2>
<br>
<h2 onclick="displayHint()" id="hint6">Click for hint</h2>
<br>
<h2 onclick="displayHint()" id="hint7">Click for hint</h2>
<br>
<script>
function displayHint() {
document.getElementById("hint1").innerHTML = hint1;
}
这适用于我的目的，但它显示了实际网站的 HTML 中的提示（由于 PHP 的原因echo），这是我不想要的。我尝试过 AJAX（本教程中的第 1 点如何将变量和数据从 PHP 传递到 JavaScript？），但输出无法正常工作，并在单击文本时显示 [object HTMLHeadingElement]。数据库元素已正确传输到我也通过回显 PHP 变量进行了检查，结果是正确的。
斯蒂芬大帝1回答
-
跃然一笑
您需要发送一个 AJAX 请求，您需要确保这responseType是text（这是默认的，顺便说一句）并this.responseText在onreadystatechange回调中使用，如下例所示：<!DOCTYPE html><html><head><script>function showHint(str) { if (str.length == 0) { document.getElementById("txtHint").innerHTML = ""; return; } else { var xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) { document.getElementById("txtHint").innerHTML = this.responseText; } } xmlhttp.open("GET", "gethint.php?q="+str, true); xmlhttp.send(); }}</script></head><body><p><b>Start typing a name in the input field below:</b></p><form action=""> <label for="fname">First name:</label> <input type="text" id="fname" name="fname" onkeyup="showHint(this.value)"></form><p>Suggestions: <span id="txtHint"></span></p></body></html>
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