如何计算多次猜测一个数字所需的平均猜测次数
所以我们在我们的java类中制作HiLo，并且说明说玩家应该能够玩多次。所以我已经这样做了，并且还计算了猜测所有游戏数量所需的平均猜测次数，我不知道如何做到这一点，因为猜测数量在游戏重置后重置？
我对时间有同样的问题（完全相同的事情，猜测数字所需的平均时间）
我尝试过编写猜测++，但我不知道如何“存储”每个游戏所需的猜测次数，也不知道如何做到这一点
public class HiLo{
//Globala-Variabler
static int tal = 0;
static int totaltSpelade = 0;
static int gissning = 1;
static int antalGissningar = 0;
public static void main(String args[]) throws InterruptedException {
// val slingan
int val = Kbd.readInt("\nKlicka 1 för 1-10\nKlicka 2 för 1-100\nKlicka 3 för 1-1000");
if (val == 1){
tal = (int) (Math.random() * 10)+1;
}
else if (val == 2){
tal = (int) (Math.random() * 100)+1;
}
else if (val ==3){
tal = (int) (Math.random() * 1000)+1;
}
else{
Kbd.clearScreen();
System.out.println("\nFelinmatning!");
main(null);
}
// tid och gissnings slinga
int gissningar = Kbd.readInt("\nBörja gissa!");
long startTid = System.currentTimeMillis();
slinga();
//stop tid
System.out.println("\nGrattis!\nDu gissade rätt tal på " + antalGissningar + " försök!");
long stopTid = System.currentTimeMillis();
long tid = stopTid-startTid;
System.out.print("Det tog dig! " + (tid/1000) + "s");
totaltSpelade++;
int avsluta = Kbd.readInt("\nKlicka 1 för att köra igen\nKlicka 2 för att avsluta");
if (avsluta == 1){
//Kbd.clearScreen();
main(null);
}
else{
System.out.println("\nHejdå!, Det tog dig i snitt " +
// THIS IS WHERE I WANT TO PRINT OUT THE AVERAGE NUMBER OF GUESSES OF ALL GAMES
(antalGissningar/totaltSpelade) + " gissningar per gång.");
System.out.println("\nOch i snitt " + (tid/1000) + " s");
//Kbd.clearScreen();
System.exit(0);
}
}
牧羊人nacy1回答
-
摇曳的蔷薇
我创建了一个猜数字游戏。目标是向您展示如何使用嵌套循环而不是递归调用 main 方法。它可能无法满足您的所有要求。您可以添加很多东西，例如根据难度级别计算平均猜测值。给出提示，确保用户输入的数字在难度级别等范围内......我已经在评论中解释了逻辑。public static void main(String args[]) { String playAgain = "yes"; ArrayList<Integer> totalGuesses = new ArrayList<>(); // Keep track of total guesses in all rounds int round = 1; // Round number do { // Prints greeting System.out.println("Welcome to High Low game.\nPlease enter difficulty level."); System.out.println("Level 1: Easy Range [1-10]"); System.out.println("Level 2: Medium Range [1-100]"); System.out.println("Level 3: Hard Range [1-1000]"); System.out.print("\nEnter Level Number: "); Scanner scanner = new Scanner(System.in); int difficultyLevel = scanner.nextInt(); // Making sure that user inputs difficulty level within a certain range while (!(difficultyLevel > 0 && difficultyLevel <= 3)) { System.out.print("Please enter correct difficulty level: "); difficultyLevel = scanner.nextInt(); } // Displays selected difficulty level System.out.println("Difficulty level is set to " + difficultyLevel + "\n"); int theNumber = 0; if (difficultyLevel == 1) { // This part is copied from your code theNumber = (int) (Math.random() * 10) + 1; } else if (difficultyLevel == 2) { theNumber = (int) (Math.random() * 100) + 1; } else if (difficultyLevel == 3) { theNumber = (int) (Math.random() * 1000) + 1; } boolean hasGuessed = false; int numberOfGuesses = 0; // keep track of number of guesses in each round int guessedNumber; ArrayList<Integer> alreadyGuessed = new ArrayList<>(); while (!hasGuessed) { // While user has not guessed (This while loop is nested in do while) System.out.print("Please guess the number: "); guessedNumber = scanner.nextInt(); if (theNumber == guessedNumber) { // If user guesses correctly hasGuessed = true; numberOfGuesses++; System.out.printf("\nCongratulations you have guessed the number on your number %d attempt", numberOfGuesses); totalGuesses.add(new Integer(numberOfGuesses)); } else { // If guess is incorrect numberOfGuesses++; alreadyGuessed.add(new Integer(guessedNumber)); if (guessedNumber > theNumber) { System.out.println("\nSorry but the number you are trying to guess is lower that your guess"); } else { System.out.println("\nSorry but the number you are trying to guess is higher that your guess"); } // Prints already guessed so user doesn't enter same value. You can program so it doesn't accept same number by checking the guessedNumber againstalreadyGuessed System.out.println("Already guessed numbers: " + alreadyGuessed.toString()); } } // when hasGuessed is true the while loop exits System.out.print("\nDo you want to play again? Enter yes or no: "); playAgain = scanner.next(); // Asking user if they want another round if (playAgain.equalsIgnoreCase("yes")) { System.out.println("\nRound " + ++round); //Prints round number plus adds empty line between each round } } while (playAgain.equalsIgnoreCase("yes")); // If player enters anything besides yes it exits do while loop double averageGuesses = calculateAverage(totalGuesses); // Calculates average guesses System.out.println("\nYour average number of guesses are " + averageGuesses);}/* * Adds all elements in array and divides it by arraylist size */private static double calculateAverage(ArrayList<Integer> list) { Integer sum = 0; if (!list.isEmpty()) { // Iterate through list and stores each item in a variable (item) for (Integer item : list) { sum += item; // short form of sum = sum + item; } return sum.doubleValue() / list.size(); } return sum;}示例输出：Welcome to High Low game.Please enter difficulty level.Level 1: Easy Range [1-10]Level 2: Medium Range [1-100]Level 3: Hard Range [1-1000]Enter Level Number: 1Difficulty level is set to 1Please guess the number: 6Sorry but the number you are trying to guess is lower that your guessAlready guessed numbers: [6]Please guess the number: 2Sorry but the number you are trying to guess is higher that your guessAlready guessed numbers: [6, 2]Please guess the number: 5Congratulations you have guessed the number on your number 3 attemptDo you want to play again? Enter yes or no: yesRound 2Welcome to High Low game.Please enter difficulty level.Level 1: Easy Range [1-10]Level 2: Medium Range [1-100]Level 3: Hard Range [1-1000]Enter Level Number: 1Difficulty level is set to 1Please guess the number: 1Congratulations you have guessed the number on your number 1 attemptDo you want to play again? Enter yes or no: noYour average number of guesses are 2.0
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