有没有办法（永远）检查某个字符串的长度是否可以被某个数字整除？

Question

在我试图在这里编写的代码中，我需要它不断检查字符串的长度是否能被 3 整除，如果是，则输出有效输出，如果不是，则再次循环。我事先在代码中定义了所有其他变量，例如 a、u()。

def u():

  if int(len(str(a))) ('is divisible by 3'):

    print('The sum of all characters in that string is divisible by 3')

  while int(len(str(a)))  ('is not divisible by 3'):

    print('The sum of all characters in that string is NOT divisible by 3, try again!')

    u()

u()

一个简短而有效的答案将不胜感激，谢谢！

Answer 1

在这里，我使用了来自用户的输入并检查是否满足条件。def u():  a = input(' Input string ')  if int(len(str(a)))%3 ==0:   #('is divisible by 3'):      print('The sum of all characters in that string is divisible by 3')  else: # int(len(str(a)))  ('is not divisible by 3'):      print('The sum of all characters in that string is NOT divisible by 3, try again!')      u()u()