Python URL 编码问题

Question

我正在尝试修改 ANKI 插件 .py 文件，以便能够解析牛津的单词

from urllib.parse import urlencode

qs = urlencode({"q": "come along"})

URL = "https://www.oxfordlearnersdictionaries.com/search/english/?{}"

print(URL.format(qs))

我的输出

“https://www.oxfordlearnersdictionaries.com/search/english/?q=come+along”

但实际上输出应该是这样的

“https://www.oxfordlearnersdictionaries.com/definition/english/come-along?q=come+along”

我怎样才能克服这个问题我是初学者

#-- coding:utf-8 --

import random

from ..base import *

import requests

from bs4 import BeautifulSoup

from time import sleep

from random import randint

@register(u'Oxford_Article')

class Oxford_Article(WebService):

    def init(self):

        super(Oxford_Article, self).init()

    def _get_from_api(self):

        sleep(randint(1,3))

        

        param = {"q": "come along"}

        qs = urlencode(param)

        param['q'] = param['q'].replace(' ', '-')

        URL = "https://www.oxfordlearnersdictionaries.com/definition/english/{}?{}"

        

        data = self.get_response(URL.format(param['q'],qs))

        soup = parse_html(data)

        result = {

            'Article': u'',

        }

        # Article

        element = soup.find('div', id='entryContent')

        for s in element.select('script'):

            s.extract()

        if element:

            result['Article'] = u''.join(str(e) for e in element.contents)

        return self.cache_this(result)

    @export([u'entryContent', u'Article definition'])

    def fld_definate(self):

        return self._get_field('Article')

Answer 1

你可以这样做from urllib.parse import urlencodeparam = {"q": "come along"}qs = urlencode(param)param['q'] = param['q'].replace(' ', '-')URL = "https://www.oxfordlearnersdictionaries.com/definition/english/{}?{}"print(URL.format(param['q'],qs))

Answer 2

如果您在解析数据时遇到错误只需替换这段代码data = self.get_response(URL.format(param['q'],qs)) soup = parse_html(data)用这个代码page = urllib.request.urlopen(URL.format(param['q'],qs)) soup = BeautifulSoup(page)也不要忘记导入这个import urllib.request