将 PHP 数组转换为特定的 JSON 数据
我试图为 Rubrics 生成特定的 json，仅需要以下格式。
为什么我需要这个？
对于 SurveyJS，我正在使用 PHP 创建单元格 json
PHP 输出
Array
(
[Attendance] => Array
(
[0] => Array
(
[OUTSTANDING] => A
)
[1] => Array
(
[Satisfactory] => B
)
[2] => Array
(
[Needs Improvement] => C
)
[3] => Array
(
[Unacceptable] => D
)
)
[Punctuality] => Array
(
[0] => Array
(
[OUTSTANDING] => A
)
[1] => Array
(
[Satisfactory] => B
)
[2] => Array
(
[Needs Improvement] => C
)
[3] => Array
(
[Unacceptable] => D
)
)
)
我一直在努力实现和要求的输出
{
"Attendance": {
"OUTSTANDING": "A",
"Satisfactory": "B",
"Needs Improvement": "C",
"Unacceptable": "D"
},
"Punctuality": {
"OUTSTANDING": "A",
"Satisfactory": "B",
"Needs Improvement": "C",
"Unacceptable": "D"
}
}
手掌心2回答
-
慕斯王
您需要展平每个子数组。鉴于该结构，这应该有效：foreach($array as $key => $val) { $array[$key] = array_merge(...$val); }如果您有旧的 PHP 版本，那么： $array[$key] = call_user_func_array('array_merge', $val); -
郎朗坤
根据json.org规范，关联数组将转换为对象，而平面数组将转换为数组，因此您需要类似以下内容：<?php$arr = [ 'Attendance' => [ 'OUTSTANDING' => 'A', 'Satisfactory' => 'B', 'Needs Improvement' => 'C', 'Unacceptable' => 'D' ], 'Punctuality' => [ 'OUTSTANDING' => 'A', 'Satisfactory' => 'B', 'Needs Improvement' => 'C', 'Unacceptable' => 'D' ]];echo '<pre>';echo json_encode($arr, JSON_PRETTY_PRINT);
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