JavaScript 按特定常量值对多个属性上的对象数组进行排序

Question

给定一个像这样的对象：

accounts = [

  { bankType: "Checking", currency: "USD", amount: 123.45 },

  { bankType: "Saving", currency: "CAD", amount: 1.95 },

  { bankType: "Saving", currency: "USD", amount: 23.31 },

  { bankType: "Checking", currency: "CAD", amount: 1953.1 },

];

如何按数组中的对象属性进行排序，其中bankType先"Checkings"排序，然后再排序currency帐户"CAD"，以获得下面的结果？

// Sorted array of objects result

[

  { bankType: "Checking", currency: "CAD", amount: 1953.1 },

  { bankType: "Checking", currency: "USD", amount: 123.45 },

  { bankType: "Saving", currency: "CAD", amount: 1.95 },

  { bankType: "Saving", currency: "USD", amount: 23.31 },

];

问题不在于使用内置localeCompare函数按字母顺序对其进行排序，问题在于必须按Checking第一个然后按CAD第二个的特定常量值进行排序。

Answer 1

有积分系统Checking = 2CAD = 1console.log(    [        { bankType: "Checking", currency: "USD", amount: 123.45 },        { bankType: "Saving", currency: "CAD", amount: 1.95 },        { bankType: "Saving", currency: "USD", amount: 23.31 },        { bankType: "Checking", currency: "CAD", amount: 1953.1 },    ]        .sort((a, b) => {            const pointsA = (a.bankType === "Checking" ? 2 : 0) + (a.currency === "CAD" ? 1 : 0);            const pointsB = (b.bankType === "Checking" ? 2 : 0) + (b.currency === "CAD" ? 1 : 0);            return pointsB - pointsA;        }));

Answer 2

您可以按顺序比较两者：accounts.sort((a, b) =>     a.bankType.localeCompare(b.bankType) || a.currency.localeCompare(b.currency) );

Answer 3

使用Array.prototype.sort和String.prototype.localeCompare，您可以对它们进行排序。const accounts = [  { bankType: "Checking", currency: "USD", amount: 123.45 },  { bankType: "Saving", currency: "CAD", amount: 1.95 },  { bankType: "Saving", currency: "USD", amount: 23.31 },  { bankType: "Checking", currency: "CAD", amount: 1953.1 },];const output = accounts.sort((a, b) => {  const bankCompare = a.bankType.localeCompare(b.bankType);  if (bankCompare === 0) {    return a.currency.localeCompare(b.currency);  }  return bankCompare;});console.log(output);