如何移动一个精灵，将其更改为另一个精灵，然后再次移动它？

Question

我试图将一个精灵保持在屏幕中央几秒钟，然后将其平滑地向左移动，直到它离开屏幕，然后我想要一个不同的精灵，它应该从屏幕右侧移动到屏幕右侧屏幕中心；所有这一切都在无限循环中。

一个非常清楚的例子：

public Sprite Pokemon_0;

public Sprite Pokemon_1;

    void Start()

    {

    GetComponent<SpriteRenderer>().sprite = Pokemon_0;

}

    void Update()

    {

    if (transform.position.x >= -80) 

    {

        transform.Translate(-1f,0f,0f);

    }

    else

    {

        GetComponent<SpriteRenderer>().sprite = Pokemon_1;         

    }

以下是据我所知。它将精灵平滑地向左移动，直到它离开屏幕，然后将精灵更改为其他精灵。

我很新，所以如果有人可以编写一个简单的脚本，那将会非常有帮助。我也在努力学习，因此将不胜感激。

Answer 1

// The [Range()] attribute will make `speed` show up with a slider in the inspector[Range(0.1f, 5)]public float speed = 3;public Sprite[] Pokemons;private SpriteRenderer sr;private float worldMiddleX;private float worldLeftX;private float worldRightX;private int currentPokemon = 0;private float secondsInMiddle = 3f;void Start(){    sr = GetComponent<SpriteRenderer>();    sr.sprite = Pokemons[currentPokemon];    // Find out what X's in the world the left edge, middle & right of the screen is,    // if you have a 1920x1080 resolution Screen.width will be 1920. But we don't    // want to position us at x = 1920, because that is FAR away    // So we need to figure out where in the GAME world, our screen right edge is    worldMiddleX = Camera.main.ScreenToWorldPoint(new Vector2(Screen.width / 2, 0f)).x;    // +100 & -100 because we want it to go outside of the screen a little bit    // These should be tweaked based on the sprite width    // Can be done dynamically / programatically too. Their width is in    // Pokemons[0].rect.width    worldLeftX = Camera.main.ScreenToWorldPoint(new Vector2(-100, 0f)).x;    worldRightX = Camera.main.ScreenToWorldPoint(new Vector2(Screen.width + 100, 0f)).x;    // Start our endlessly looping Coroutine, which will take care of     // 1. Moving to the middle.    // 2. Waiting in middle    // 3. Moving outside of screen to the left & resetting position    // 4. Repeat    StartCoroutine(SlideLeftButWaitMiddleEndlesslyLoop());}/** Changed from void to IEnumerator to get access to the* `yield` keyword, which will let us pause execution for X seconds.* If you do this with a normal method, you will need to invoke it with* `StartCoroutine()` as it becomes a Coroutine, which will execute in * an asynchronous manner*/IEnumerator SlideLeftButWaitMiddleEndlesslyLoop(){    while (true)    {        // yield return *Coroutine* will make sure that the code doesn't continue         // its code path until it has completed its Coroutine (method execution)        // Wait for MoveToMiddle() to finish executing        yield return StartCoroutine(MoveToMiddle());        // Wait for x seconds        yield return new WaitForSeconds(secondsInMiddle);        // Wait for MoveOutsideScreenAndReset() to finish executing        yield return StartCoroutine(MoveOutsideScreenAndReset());    }}IEnumerator MoveToMiddle(){    while (transform.position.x > worldMiddleX)    {        transform.Translate(-(speed * Time.deltaTime), 0f, 0f);        yield return null;        // yield return null here will make this loop pause until next frame        // so that it doesn't just do all the loops instantly and teleport your sprite    }}IEnumerator MoveOutsideScreenAndReset(){    while (transform.position.x > worldLeftX)    {        transform.Translate(-(speed * Time.deltaTime), 0f, 0f);        yield return null;        // yield return null here will make this loop pause until next frame        // so that it doesn't just do all the loops instantly and teleport your sprite    }    // Change to the next sprite    nextPokemonSprite();    // Reset the position, then the Update() method will start again from the top    // since this method will have fully executed    Vector3 pos = transform.position;    pos.x = worldRightX;    transform.position = pos;}// If we're at the last Pokemon in the Pokemons array, start over at 0void nextPokemonSprite(){    currentPokemon++;    if (currentPokemon == Pokemons.Length)        currentPokemon = 0;    sr.sprite = Pokemons[currentPokemon];}