Lodash，找到给定 ids 数组的每个对象

Question

我所拥有的有效，但我怀疑有一个 lodash 方法可以在没有 _.map() 的情况下完成此操作。

const _ = require('lodash')

const ids = [1, 2]

const objects = [

  {

    id: 1,

    foo: 'bar'

  }, {

    id: 2,

    foo: 'baz'

  }, {

    id: 3,

    foo: 'quux'

  }

]

const result = _.map(ids, id => _.find(objects, { id }))

console.log(result)

// => [ { id: 1, foo: 'bar' }, { id: 2, foo: 'baz' } ]

谢谢！

Answer 1

您可以使用_.intersectionWith()从数组中获取项目objects，它id等于ids数组中的项目：const ids = [1, 2]const objects = [{ id: 1, foo: 'bar' }, { id: 2, foo: 'baz' }, { id: 3, foo: 'quux' }]const result = _.intersectionWith(objects, ids, (o, id) => o.id === id)console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.20/lodash.min.js" integrity="sha512-90vH1Z83AJY9DmlWa8WkjkV79yfS2n2Oxhsi2dZbIv0nC4E6m5AbH8Nh156kkM7JePmqD6tcZsfad1ueoaovww==" crossorigin="anonymous"></script>另一种选择是将数组转换为using (the )objects的对象，然后使用using 从字典中获取项目：{ [id]: obj }_.keyBy()id_.at()_.at()const ids = [1, 2]const objects = [{ id: 1, foo: 'bar' }, { id: 2, foo: 'baz' }, { id: 3, foo: 'quux' }]const result = _.at(_.keyBy(objects, 'id'), ids)console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.20/lodash.min.js" integrity="sha512-90vH1Z83AJY9DmlWa8WkjkV79yfS2n2Oxhsi2dZbIv0nC4E6m5AbH8Nh156kkM7JePmqD6tcZsfad1ueoaovww==" crossorigin="anonymous"></script>