Django：不同模型中的全局搜索 - 发布结果不出现
我希望你很好。我在不同的应用程序中创建了一个具有多个模型的全局搜索。
帖子模型属于 Nutriscore 文件夹
UserProfile 模型属于 User 文件夹
如果我使用一个涵盖帖子和用户配置文件搜索的单词，例如主课程。我得到了 UserProfile 的一些搜索结果（3 个结果），但 Post 没有出现任何内容（而count给了我 6 个结果）。所以我不知道代码有什么问题？
用户/视图.py
# global search
class GlobalSearchView(ListView):
template_name = 'search_global.html'
count = 0
countnutri = 0
def get_context_data(self, *args, **kwargs):
context = super().get_context_data(*args, **kwargs)
context['count'] = self.count or 0
context['countnutri'] = self.countnutri or 0
context['query'] = self.request.GET.get('q')
return context
def get_queryset(self): # new
query = self.request.GET.get('q', None)
if query is not None:
nutriscore = Post.objects.filter(
Q(title__icontains=query) | Q(slug__icontains=query) | Q(typederepas__name__icontains=query) | Q(prixrepas__name__icontains=query) | Q(vitesserepas__name__icontains=query) | Q(force__name__icontains=query) | Q(bienfaitrepas__name__icontains=query)
).distinct()
user = UserProfile.objects.filter(
Q(pays__icontains=query) | Q(town__icontains=query) | Q(user__username__icontains=query) | Q(mealtrend__name__icontains=query) | Q(pricetrend__name__icontains=query) | Q(speedtrend__name__icontains=query)| Q(strengthtrend__name__icontains=query) | Q(wellnesstrend__name__icontains=query)
).distinct()
results = chain(nutriscore,user)
qs = sorted(user,
key=lambda instance: instance.pk,
reverse=True)
self.count = len(qs)
qn = sorted(nutriscore,
key=lambda instance: instance.pk,
reverse=True)
self.countnutri = len(qn)
return qs
return qn
return results
温温酱3回答
-
梵蒂冈之花
免责声明：这个答案可能不适合OP的观点或模型，但是，它将按原样与示例一起工作。为了清楚起见，我假设我们有两个模型，Musician 它们Album位于sample应用程序中。# sample/models.pyfrom django.db import modelsclass Musician(models.Model): name = models.CharField(max_length=50) def __str__(self): return f'{self.name}'class Album(models.Model): artist = models.ForeignKey(Musician, on_delete=models.CASCADE) name = models.CharField(max_length=100) description = models.TextField() def __str__(self): return f'{self.name} : {self.artist}'然后，我们必须创建一个mixin类，以获得更好的OOP 体验以及跨多个视图的可扩展性。#sample/mixins.pyfrom django.apps import appsfrom django.db.models import Qfrom functools import reducefrom operator import or_class SearchMixin: search_keyword_arg = 'q' search_settings = {} lookup_expr = 'icontains' def get_search_term(self): return self.request.GET.get(self.search_keyword_arg) def build_search_query(self, model_ref, term): return reduce(or_, [Q(**{f'{field}__{self.lookup_expr}': term}) for field in self.search_settings[model_ref]]) def get_search_results(self): has_search_result = False search_term = self.get_search_term() if not search_term: return {'has_search_result': has_search_result} results = {} for model_ref, fields in self.search_settings.items(): app_name, model_str = model_ref.split('.') ModelKlass = apps.get_model(app_label=app_name, model_name=model_str) qs = ModelKlass.objects.filter(self.build_search_query(model_ref, search_term)) results[model_ref.replace('.', '_').lower()] = qs if has_search_result is False and qs.exists(): has_search_result = True results['has_search_result'] = has_search_result return results def get_context_data(self, **kwargs): context = super().get_context_data(**kwargs) context['search_result'] = self.get_search_results() return context这个SearchMixin类有我们想要的搜索功能。我们可以将此类添加到任何 Django 视图中来获取结果。为此，我们将SearchMixinclass 继承为ListViewas，# sample/views.pyfrom django.views.generic import TemplateViewfrom sample.mixins import SearchMixinclass GlobalSearchView(SearchMixin, TemplateView): template_name = 'sample/global_search.html' search_settings = { 'sample.Musician': ['name'], 'sample.Album': ['name', 'description'], }笔记：我使用了TemplateView更适合这种特殊情况的方法。有一个名为的新类属性search_settings，用于确定搜索字段。search_settings属性应该如何？它必须是一个dict（或dict类似的对象）对象的键dict应该采用以下app_name.ModelClassName格式的值dict必须是模型字段的可迭代它在模板中看起来怎么样？该类SearchMixin将搜索结果添加到名为 and 的上下文变量中，search_result该变量还有另一个变量has_search_result( search_result.has_search_result)，可用于检查我们是否有“任何匹配”。此外，每个查询集都可以通过单独的变量访问。变量的格式为， app_name<underscore><model_name_in_lower_case>.例如，对于模型，可以在模板中sample.Musician获取搜索结果（如果有），如下所示：{{ search_result.sample_musician }}# sample/templates/sample/global_search.html{% if search_result.has_search_result %} <strong>Musician result</strong><br> {% for musician in search_result.sample_musician %}<br> {{ musician.name }} {% endfor %} <br><br> <strong>Album result</strong><br> {% for album in search_result.sample_album %} {{ album.name }} -- {{ album.description }}<br> {% endfor %}{% else %} No match{% endif %}现在，连接视图urls.py并使用查询参数进行搜索，如下所示：/foo-bar/global-search/?q=xx -
元芳怎么了
我认为最好将所有内容都get_context_data这样放入： # global search class GlobalSearchView(ListView): template_name = 'search_global.html' count = 0 countnutri = 0 def get_context_data(self, *args, **kwargs): context = super().get_context_data(*args, **kwargs) context['count'] = self.count or 0 context['countnutri'] = self.countnutri or 0 query = self.request.GET.get('q', None) context['query'] = query if query: nutriscore = Post.objects.filter( Q(title__icontains=query) | Q(slug__icontains=query) | Q(typederepas__name__icontains=query) | Q(prixrepas__name__icontains=query) | Q(vitesserepas__name__icontains=query) | Q(force__name__icontains=query) | Q(bienfaitrepas__name__icontains=query) ).distinct() user = UserProfile.objects.filter( Q(pays__icontains=query) | Q(town__icontains=query) | Q(user__username__icontains=query) | Q(mealtrend__name__icontains=query) | Q(pricetrend__name__icontains=query) | Q(speedtrend__name__icontains=query)| Q(strengthtrend__name__icontains=query) | Q(wellnesstrend__name__icontains=query) ).distinct() context['results'] = chain(nutriscore,user) return contextresults然后您可以在模板中使用变量 -
精慕HU
你有 3 个 return 语句，所以只有第一个会被执行： return qs # return user return qn # return nutriscore / NOT EXECUTED return results # return results / NOT EXECUTED你应该只保留return results.如果您确实想返回 3 个项目，请以元组形式返回： return qa, qn, results
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