我有下一个 GORM 模型
package entity
import (
"github.com/jinzhu/gorm"
)
type InterfaceEntity interface {
}
type User struct {
InterfaceEntity
gorm.Model
Name string
}
我尝试将 GORM 实体类型传递到基础 crud 存储库中。我的基础 crud 存储库:
package repository
import (
"billingo/model/entity"
"fmt"
"github.com/jinzhu/gorm"
"reflect"
)
type CrudRepository struct {
*BaseRepository
}
func NewCrudRepository(db *gorm.DB) CrudRepositoryInterface {
repo := NewBaseRepository(db).(*BaseRepository)
return &CrudRepository{repo}
}
func (c CrudRepository) Find(id uint, item entity.InterfaceEntity) entity.InterfaceEntity {
fmt.Println("--- Initial")
var local entity.User
fmt.Println("--- local: ", reflect.TypeOf(local), local)
fmt.Println("--- Item: ", reflect.TypeOf(item), item)
fmt.Println("--- Values")
c.db.First(&local, id)
fmt.Println("--- local: ", reflect.TypeOf(local), local)
c.db.First(&item, id)
fmt.Println("--- Item: ", reflect.TypeOf(item), item)
return item
}
正如您在这里看到的,方法中有item和local变量Find()。
我item通过服务的下一种方式传递:
func (c CrudService) GetItem(id uint) entity.InterfaceEntity {
var item entity.User
return c.repository.Find(id, item)
}
看来whatlocal和item必须是equals和behavior必须是等价的。
但是输出是
--- Initial
--- local: entity.User {<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }
--- Item: entity.User {<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }
--- Values
--- local: entity.User {<nil> {1 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} test 1}
--- Item: entity.User {<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }
INFO[0000] User info user="{<nil> {0 0001-01-01 00:00:00 +0000 UTC 0001-01-01 00:00:00 +0000 UTC <nil>} }" user-id=1
(/home/mnv/go/src/billingo/model/repository/CrudRepository.go:29)
[2019-05-17 17:07:37] unsupported destination, should be slice or struct
item从服务传递到消息
不支持的目标,应该是 slice 或 struct
如何item正确通过,我需要像 with 这样的行为local?
墨色风雨
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