我正在实施一个可以从渠道获取工作的工作人员池。一直超时后,我发现当一个worker fcn内部发生panic时,即使我做了恢复机制,worker还是不会再回到pool中。
在 golang 操场上,我能够重现这个问题:
修改后的游乐场代码:
package main
import "fmt"
import "time"
import "log"
func recovery(id int, results chan<- int) {
if r := recover(); r != nil {
log.Print("IN RECOVERY FUNC - Failed worker: ",id)
results <- 0
}
}
func worker(id int, jobs <-chan int, results chan<- int) {
for j := range jobs {
defer recovery(id, results)
if id == 1 {
panic("TEST")
}
fmt.Println("worker", id, "started job", j)
time.Sleep(time.Second)
fmt.Println("worker", id, "finished job", j)
results <- j * 2
}
}
func main() {
jobs := make(chan int, 100)
results := make(chan int, 100)
for w := 1; w <= 3; w++ {
go worker(w, jobs, results)
}
for j := 1; j <= 10; j++ {
jobs <- j
}
close(jobs)
for a := 1; a <= 10; a++ {
<-results
}
}
为了测试,我在使用 worker 1 时实施了恐慌。运行时,函数会按预期发生恐慌,并按预期进入恢复状态(也不会将值推送到通道中),但是 worker 1 似乎永远不会回来。
没有恐慌的输出:
worker 3 started job 1
worker 1 started job 2
worker 2 started job 3
worker 1 finished job 2
worker 1 started job 4
worker 3 finished job 1
worker 3 started job 5
worker 2 finished job 3
worker 2 started job 6
worker 3 finished job 5
worker 3 started job 7
worker 1 finished job 4
worker 1 started job 8
worker 2 finished job 6
worker 2 started job 9
worker 1 finished job 8
worker 1 started job 10
worker 3 finished job 7
worker 2 finished job 9
worker 1 finished job 10
恐慌输出:
worker 3 started job 1
2009/11/10 23:00:00 RECOVERY Failed worker: 1
worker 2 started job 3
worker 2 finished job 3
worker 2 started job 4
worker 3 finished job 1
worker 3 started job 5
worker 3 finished job 5
worker 3 started job 6
worker 2 finished job 4
worker 2 started job 7
worker 2 finished job 7
worker 2 started job 8
worker 3 finished job 6
worker 3 started job 9
worker 3 finished job 9
worker 3 started job 10
worker 2 finished job 8
worker 3 finished job 10
恢复后(或在恢复过程中)如何将工作人员 1 返回池中
翻翻过去那场雪
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