在 JavaScript 中计算时间总和

Question

我在 mongodb 中有记录，时间是字符串。

**Time**   

       

00:10:40

00:40:10

01:10:20

00:43:40

00:42:40

00:30:40

00:54:10

00:47:40

00:50:40

01:05:40

00:45:40

00:51:40

00:36:40

如何计算整个时间的总和？

Answer 1

你的时间字符串在数组中吗？你可以使用这样的东西：var hours = 0;var minutes = 0;var seconds = 0;var sum = '';var myArray = ["01:40:40","03:50:50"];var myFunction = function(){  for(var i in myArray){   hours += parseInt(myArray[i].substring(0, 2))   minutes += parseInt(myArray[i].substring(3, 5))   seconds += parseInt(myArray[i].substring(6))  }  if(seconds > 59){    minutes += parseInt(seconds / 60);    seconds = parseInt(seconds % 60);  }    if(minutes > 59){    hours += parseInt(minutes / 60);    minutes = parseInt(minutes % 60);  }  sum = hours + ":" + minutes + ":" + seconds;    console.log(sum);}myFunction();如果您有任何其他问题，请随时询问。

Answer 2

**This may also work  :**     var time1 = "01:00:00";    var time2 = "00:30:00";    var time3 = "00:30:00";    var hour=0;    var minute=0;    var second=0;    var splitTime1= time1.split(':');    var splitTime2= time2.split(':');    var splitTime3= time3.split(':');        hour = parseInt(splitTime1[0])+parseInt(splitTime2[0])+parseInt(splitTime3[0]);    minute = parseInt(splitTime1[1])+parseInt(splitTime2[1])+parseInt(splitTime3[1]);    hour = hour + minute/60;    minute = minute%60;    second = parseInt(splitTime1[2])+parseInt(splitTime2[2])+parseInt(splitTime3[2]);    minute = minute + second/60;    second = second%60;        alert('sum of above time= '+hour+':'+minute+':'+second);