我有一个 websocket 客户端。实际上,它比下面显示的基本代码复杂得多。我现在需要扩展此客户端代码以打开到多个服务器的连接。最终,从服务器接收到消息时需要执行的任务是相同的。处理这个问题的最佳方法是什么?正如我上面所说,接收消息时执行的实际代码比示例中显示的要复杂得多。
package main
import (
"flag"
"log"
"net/url"
"os"
"os/signal"
"time"
"github.com/gorilla/websocket"
)
var addr = flag.String("addr", "localhost:1234", "http service address")
func main() {
flag.Parse()
log.SetFlags(0)
interrupt := make(chan os.Signal, 1)
signal.Notify(interrupt, os.Interrupt)
// u := url.URL{Scheme: "ws", Host: *addr, Path: "/echo"}
u := url.URL{Scheme: "ws", Host: *addr, Path: "/"}
log.Printf("connecting to %s", u.String())
c, _, err := websocket.DefaultDialer.Dial(u.String(), nil)
if err != nil {
log.Fatal("dial:", err)
}
defer c.Close()
done := make(chan struct{})
go func() {
defer close(done)
for {
_, message, err := c.ReadMessage()
if err != nil {
log.Println("read:", err)
return
}
log.Printf("recv: %s", message)
}
}()
ticker := time.NewTicker(time.Second)
defer ticker.Stop()
for {
select {
case <-done:
return
case t := <-ticker.C:
err := c.WriteMessage(websocket.TextMessage, []byte(t.String()))
if err != nil {
log.Println("write:", err)
return
}
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