使用 JSON-B 反序列化 JSON 数组

Question

我正在尝试使用 JSONB 反序列化 JSON 数组。

JSON

[

  {

    "id": "1",

    "animal": "dog",

    "age": "3"

  },

  {

    "id": "2",

    "animal": "cat",

    "age": "5"

  }

]

控制器

Jsonb jsonb = JsonbBuilder.create();    

Animal animal;

AnimalsList animalsList;

public AnimalsList getAnimals() {

    try {

        animalsList = jsonb.fromJson("[{\"id\":\"1\",\"animal\":\"dog\",\"age\":\"3\"},{\"id\":\"2\",\"animal\":\"cat\",\"age\":\"5\"}]", AnimalsList.class);

    } catch (JSONException ex) {

        Logger.getLogger(Controller.class.getName()).log(Level.SEVERE, null, ex);

    }

    return animalsList;

}

动物清单

public class AnimalsList implements Serializable{

    private List<Animal> list;

    public AnimalsList() {

    }

    public AnimalsList(List<Animal> list) {

        this.list = list;

    }

    // getter & setter

}

动物

public class Animal implements Serializable{

    private int id;

    private String animal;

    private int age;

    public Animal() {

    }

    public Animal(int id, String animal, int age) {

        this.id = id;

        this.animal = animal;

        this.age = age;

    }

    // getter & setter

}

但我收到以下错误：

javax.json.bind.JsonbException: Can't deserialize JSON array into: class com.model.AnimalsList

Answer 1

List<Dog> dogs = new ArrayList<>();dogs.add(falco);dogs.add(cassidy);// Create Jsonb and serializeJsonb jsonb = JsonbBuilder.create();String result = jsonb.toJson(dogs);// Deserialize backdogs = jsonb.fromJson(result, new ArrayList<Dog>(){}.getClass().getGenericSuperclass());

Answer 2

如果您不限于仅使用 JSON-B，则可以通过 TypeReferencing 使用 ObjectMapper 来完成。private ObjectMapper objectMapper = new ObjectMapper();List<Animal> animals = objectMapper.readValue(json , new TypeReference<List<Animal>>(){});