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慕村9548890
此示例将打印从第一个地址 62.76.47.12/28 到 62.76.47.9 的地址。游乐场: https: //play.golang.org/p/MUtbiKaQ_3-package mainimport ( "fmt" "net")func main() { cidr := "62.76.47.12/28" _, ipnet, _ := net.ParseCIDR(cidr) ipFirst := ipnet.IP ipFirstValue := toHost(ipFirst) ipLast := net.ParseIP("62.76.47.9") ipLastValue := toHost(ipLast) fmt.Println("cidr: ", cidr) fmt.Println("first: ", ipFirst) fmt.Println("last: ", ipLast) if ipLastValue < ipFirstValue { fmt.Println("ugh") return } for i := ipFirstValue; i < ipLastValue; i++ { addr := toIP(i) fmt.Println(addr) }}func toHost(ip net.IP) uint32 { i := ip.To4() return uint32(i[0])<<24 + uint32(i[1])<<16 + uint32(i[2])<<8 + uint32(i[3])}func toIP(v uint32) net.IP { v3 := byte(v & 0xFF) v2 := byte((v >> 8) & 0xFF) v1 := byte((v >> 16) & 0xFF) v0 := byte((v >> 24) & 0xFF) return net.IPv4(v0, v1, v2, v3)}
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富国沪深
如果你打印ìpMax,你会看到它的底层表示使用了 16 个字节。(另请参阅文档fmt.Printf("'%#v'\n",ipMax)'net.IP{0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0xff, 0xff, 0x3e, 0x4c, 0x2f, 0x9}'您可以转换ipMax为 IPv4 表示以获得所需的结果:ipMax := net.ParseIP("62.76.47.9").To4()
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皈依舞
使用IPAddress Go library,我可以提供两种方法,一种方法类似于您通过迭代整个子网的建议,另一种方法是从给定地址开始并递增直到达到最大地址。请注意,这些解决方案与 IPv6 的工作方式相同。免责声明:我是项目经理。62.76.47.12/28请注意,和 的封闭 CIDR 子网62.76.47.9/28是62.76.47.0/28,因此您实际上不需要同时提供62.76.47.12/28和62.76.47.9,您可以简单地提供单个字符串62.76.47.9/28。但是为了坚持您提出的示例,我将使用这两个字符串。import ( "fmt" "github.com/seancfoley/ipaddress-go/ipaddr")func main() { cidrString, addrString := "62.76.47.12/28", "62.76.47.9" addr := ipaddr.NewIPAddressString(addrString).GetAddress() cidrAddr := ipaddr.NewIPAddressString(cidrString).GetAddress() iterateThroughSubnet(addr, cidrAddr) // solution 1 incrementAddressToMax(addr, cidrAddr) // solution 2}func iterateThroughSubnet(addr, cidrAddr *ipaddr.IPAddress) { block := cidrAddr.ToPrefixBlock().WithoutPrefixLen() fmt.Printf("\nstarting with block %s, equivalent to %v,\nand address %s\n", cidrAddr.ToPrefixBlock(), block, addr) iterator := block.Iterator() for next := iterator.Next(); next != nil; next = iterator.Next() { fmt.Printf("compare %s with %s: %d\n", next, addr, next.Compare(addr)) }}func incrementAddressToMax(addr, cidrAddr *ipaddr.IPAddress) { block := cidrAddr.ToPrefixBlock() max := block.GetUpper() fmt.Printf("\nstarting with block %s and address %s,\n"+ "incrementing to block max %s\n", block, addr, max) for ; addr.Compare(max) <= 0; addr = addr.Increment(1) { fmt.Println(addr) }}输出:starting with block 62.76.47.0/28, equivalent to 62.76.47.0-15,and address 62.76.47.9compare 62.76.47.1 with 62.76.47.9: -1compare 62.76.47.2 with 62.76.47.9: -1compare 62.76.47.3 with 62.76.47.9: -1compare 62.76.47.4 with 62.76.47.9: -1compare 62.76.47.5 with 62.76.47.9: -1compare 62.76.47.6 with 62.76.47.9: -1compare 62.76.47.7 with 62.76.47.9: -1compare 62.76.47.8 with 62.76.47.9: -1compare 62.76.47.9 with 62.76.47.9: 0compare 62.76.47.10 with 62.76.47.9: 1compare 62.76.47.11 with 62.76.47.9: 1compare 62.76.47.12 with 62.76.47.9: 1compare 62.76.47.13 with 62.76.47.9: 1compare 62.76.47.14 with 62.76.47.9: 1compare 62.76.47.15 with 62.76.47.9: 1starting with block 62.76.47.0/28 and address 62.76.47.9,incrementing to block max 62.76.47.15/2862.76.47.962.76.47.1062.76.47.1162.76.47.1262.76.47.1362.76.47.1462.76.47.15对于小子网,这两种方法可能同样有效,但是随着子网变大,您希望避免第一个递增遍历整个子网的解决方案。如果需要,使用GetNetIp的方法ipaddr.IPAddress切换到net.IP。