如何从数组中选择最高的 3 个字符串值

3回答

BIG阳

您可以排序String#localeCompare并选择按点值列排序。最后取前三项Array#slice。const array = [{ orgId: 101, dId: 494, name: "Test1", sequesnce: "6.408.06.0 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR" }, { orgId: 102, dId: 442, name: "Test2", sequesnce: "9.80.709.5 Sequesnce Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR" }, { orgId: 103, sequesnce: "9.138.309.0 Sequesnce Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR", dId: 494, name: "Test3" }, { orgId: 103, sequesnce: "8.208.409.0 Sequesnce Date : Mon 10/03/2019 (Sections: P4.568787) Spain HR", dId: 494, name: "Test3" }, { orgId: 103, sequesnce: "9.408.90.3 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR", dId: 494, name: "Test3" }], top3 = array .sort((a, b) => b.sequesnce.localeCompare(a.sequesnce, undefined, { numeric: true, sensitivity: 'base' })) .slice(0, 3)console.log(top3);.as-console-wrapper { max-height: 100% !important; top: 0; }

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慕慕森

如果序列较短且前导值较高，则需要在排序前扩展元组 - 这不适用于 localeCompareconst maxLen = 4;const expandTuple = tpl => {  tpl = tpl.split('.');  while (tpl.length < maxLen) tpl.unshift("000");  return tpl.map(x => x.padStart(3, "0")).join('.');};const array1 = [{ "orgId": 101, "dId": 494, "name": "Test1",    "sequence": "6.408.06.0 Sequence Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR" },{"orgId": 102,"dId": 442,"name": "Test2",    "sequence": "9.80.709.5 Sequence Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR",},{"orgId": 103,    "sequence": "99.1.1 NOTE THIS IS SHORTER Sequence Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR","dId": 494,"name": "Test3",},{"orgId": 103,    "sequence": "8.208.409.0 Sequence Date : Mon 10/03/2019 (Sections: P4.568787) Spain HR","dId": 494,"name": "Test3",},{"orgId": 103,    "sequence": "9.408.90.3 Sequence Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR","dId": 494,   "name": "Test3",  }]const three = array1.sort((a,b) => {  const aTub = a.sequence.split(" ")[0];  const bTub = b.sequence.split(" ")[0];  if (expandTuple(aTub)<expandTuple(bTub)) return 1  if (expandTuple(aTub)>expandTuple(bTub)) return -1  return 0;}).slice(0,3)console.log(three)// ---- compare other solution which fails on the shorter sequenceconsole.log(array1  .sort((a, b) => b.sequence.localeCompare(a.sequence, undefined, { numeric: true, sensitivity: 'base' }))  .slice(0, 3))

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肥皂起泡泡

首先，使用Array.map，您可以仅生成项目对象数组sequesne。并使用Array.sort，您可以按降序对数组进行排序。并使用Array.splice，您可以从排序数组中提取前 3 项。const array1 = [{    "orgId": 101,    "dId": 494,    "name": "Test1",    "sequesnce": "6.408.06.0 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR"  },  {    "orgId": 102,    "dId": 442,    "name": "Test2",    "sequesnce": "9.80.709.5 Sequesnce Date : Mon 06/04/2019 (Sections: P4.00344) Italy CR",  },  {    "orgId": 103,    "sequesnce": "9.138.309.0 Sequesnce Date : Mon 06/03/2019 (Sections: P4.45600) Spain HR",    "dId": 494,    "name": "Test3",  },  {    "orgId": 103,    "sequesnce": "8.208.409.0 Sequesnce Date : Mon 10/03/2019 (Sections: P4.568787) Spain HR",    "dId": 494,    "name": "Test3",  },  {    "orgId": 103,    "sequesnce": "9.408.90.3 Sequesnce Date : Mon 08/06/2019 (Sections: P4.00344) Italy CR",    "dId": 494,    "name": "Test3",  }];const sortedArr = array1.map(({ sequesnce }) => ({ sequesnce })).sort((a, b) => (b.sequesnce.localeCompare(a.sequesnce, undefined, { numeric: true, sensitivity: 'base'})));const topCount = 3;console.log(sortedArr.splice(0, topCount));

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