为什么我不能在 tkinter 画布中绘制 numpy 矩阵？

Question

我正在尝试使用 numpy、matplotlib 和 tkinter 创建生命游戏。我打算首先询问用户游戏板上的行数和列数，以及一个单元格存活的概率。输入这些信息后，用户将按下“生成”按钮开始游戏。但是，无论何时按下按钮，都会弹出错误：“AttributeError: 'numpy.ndarray' object has no attribute 'set_canvas'”。我不知道为什么 FigureCanvasTkAgg 不能绘制一个 numpy 矩阵。有没有什么方法可以在 tkinter 窗口中绘制一个 numpy 矩阵？这是我的代码：

from tkinter import *

import numpy as np

import matplotlib.pyplot as plt

from board import Board

from PIL import Image, ImageTk

from matplotlib.backends.backend_tkagg import (

    FigureCanvasTkAgg, NavigationToolbar2Tk)

def num():

    n1 = int(t1.get())

    n2 = int(t2.get())

    n3 = int(t3.get()) / 100.00

    initBoard = np.zeros((n1, n2))

    for row in range(0,n1):

            for column in range(0,n2):

                initBoard[row][column] = np.random.choice(np.arange(0, 2), p = [1 - n3, n3])

    #game_board = Board(n1, n2, initBoard)

    canvas = FigureCanvasTkAgg(initBoard, master=root)  # A tk.DrawingArea.

    canvas.draw()

    canvas.get_tk_widget().grid(row = 4, column = 0)

    root.quit()

root = Tk()

root.title('Game of Life')

root.geometry('800x600')

Label(root, text="How many rows?: ").grid(row = 0)

Label(root, text="How many columns?: ").grid(row = 1)

Label(root, text="Probability of spawn (between 0 and 100): ").grid(row = 2)

t1 = Entry(root)

t2 = Entry(root)

t3 = Entry(root)

t1.grid(row = 0, column = 1)

t2.grid(row = 1, column = 1)

t3.grid(row = 2, column = 1)

Button(root, text = 'Generate', command = num).grid(row = 3, column = 1, sticky = W, pady = 4)

fig= plt.figure()

canvas = FigureCanvasTkAgg(fig, master=root)  # A tk.DrawingArea.

canvas.draw()

canvas.get_tk_widget().grid(row = 4, column = 0)

mainloop()

Answer 1

您的代码中至少有两个问题：您没有使用FigureCanvasTkAgg正确的方法，此类创建了一个包含 matplotlib 图的画布，您可以将其集成到您的 tkinter 应用程序中。然而，这不是用这个类来绘制你的情节，而是用类AxesSubplot（即 中的子图Figure）。以下是如何创建 matplotlib 图并将其集成到 tkinter 应用程序中：fig = plt.figure()  # matplotlib figureax = fig.subplot_add(111)  # subplot inside figurecanvas = FigureCanvasTkAgg(fig, master=root)  # integrate the figure in a tkinter widgetcanvas.get_tk_widget().grid(row = 4, column = 0)  # display figure in tkinter app现在，如果你想在图中绘制一些东西，只需使用ax.plot(...)（或任何其他绘图函数）。在你的例子中，因为你想显示一个二维数组，所以你可能想使用ax.imshow(initBoard).你退出root，num()这也会破坏包含你的图形的窗口。我宁愿做的是创建一个Toplevel向用户询问参数的问题，并关闭这个顶层，而不是num().完整代码：from tkinter import *  # not a good idea in my opinion, can lead to accidental                        # naming conflicts, "import tkinter as tk" is a better alternativeimport numpy as npimport matplotlib.pyplot as plt#~from board import Boardfrom PIL import Image, ImageTkfrom matplotlib.backends.backend_tkagg import (    FigureCanvasTkAgg, NavigationToolbar2Tk)def num():    n1 = int(t1.get())    n2 = int(t2.get())    n3 = int(t3.get()) / 100.00    top.destroy()  # close dialog    initBoard = np.zeros((n1, n2))    for row in range(0, n1):        for column in range(0, n2):            initBoard[row][column] = np.random.choice(np.arange(0, 2), p=[1 - n3, n3])    #game_board = Board(n1, n2, initBoard)    ax.imshow(initBoard)  # draw board    canvas.draw_idle()  # update matplotlib figureroot = Tk()root.title('Game of Life')root.geometry('800x600')# create matplotlib figurefig = plt.figure()ax = fig.add_subplot(111)  # create axisax.axis('off')canvas = FigureCanvasTkAgg(fig, master=root)  # A tk.DrawingArea.canvas.get_tk_widget().grid(row=4, column=0)# toplevel to choose parameterstop = Toplevel(root)Label(top, text="How many rows?: ").grid(row=0)Label(top, text="How many columns?: ").grid(row=1)Label(top, text="Probability of spawn (between 0 and 100): ").grid(row=2)t1 = Entry(top)t2 = Entry(top)t3 = Entry(top)t1.grid(row=0, column=1)t2.grid(row=1, column=1)t3.grid(row=2, column=1)Button(top, text='Generate', command=num).grid(row=3, column=1, sticky=W, pady=4)mainloop()