如何在 tkinter 列表框中对齐文本

Question

我想在 tkinter 列表框中对齐文本。我有一个带有 reg 的字典列表。号码、姓名和电子邮件作为每个字典中的键。我遍历了列表并希望三个属性以这样的方式对齐，即这些词之间的距离相等。因此，每一行中的每个单词都必须从与之前/之后行中的单词相同的位置开始。但是由于不同的名称长度，对齐被打乱了。在上面的代码中，为了简单起见，我刚刚为 4 个学生创建了 4 个词典，但实际上我必须管理 50 多个学生。除了列表框之外，还有另一种简单的方法来显示此数据，条件与上述相同吗？

from tkinter import *

root = Tk()

students_Box = LabelFrame(root,

                    text = 'Registered Students', bd = 4,

                    relief = GROOVE, labelanchor = 'n',

                    font = 'Arial 10 bold', fg = 'navy blue',

                    width = 850, height = 180)

                            

students_Box.grid_propagate(0)

students_Box.pack(pady = 15)

scrollbar = Scrollbar(students_Box)

scrollbar.pack(side = RIGHT, fill = Y)

listbox = Listbox(students_Box, width = 90, bg = 'azure', font = 'TkDefaultFont 11')

listbox.pack(padx = 5, pady = 10)

allStudents = [{'Reg': '2018-MC-01', 'Name': 'Usman Khan', 'Email': '[e-mail]'},

            {'Reg': '2018-MC-02', 'Name': 'Muhammad Ehtisham Zafar', 'Email': '[e-mail]'},

            {'Reg': '2018-MC-03', 'Name': 'Ali Khan', 'Email': '[e-mail]'},

            {'Reg': '2018-MC-04', 'Name': 'Abdullah Akram', 'Email': '[e-mail]'}]   # A List of Dictionaries

for i in range(len(allStudents)):

        listbox.insert(END, f"{allStudents[i]['Reg']}     {allStudents[i]['Name']}{' '*20}{allStudents[i]['Email']}")

listbox.configure(yscrollcommand = scrollbar.set)

scrollbar.configure(command = listbox.yview)

mainloop()

Answer 1

直接的方法是使用。ttk.Treeview根据您的情况解决方案（使用ljust填充它们）：from tkinter import *root = Tk()students_Box = LabelFrame(root,                          text='Registered Students', bd=4,                          relief=GROOVE, labelanchor='n',                          font='Arial 10 bold', fg='navy blue',                          width=850, height=180)students_Box.grid_propagate(0)students_Box.pack(pady=15)scrollbar = Scrollbar(students_Box)scrollbar.pack(side=RIGHT, fill=Y)listbox = Listbox(students_Box, width=90, bg='azure', font='TkDefaultFont 11')listbox.pack(padx=5, pady=10)allStudents = [{'Reg': '2018-MC-01', 'Name': 'Usman Khan', 'Email': '[e-mail]'},               {'Reg': '2018-MC-02', 'Name': 'Muhammad Ehtisham Zafar', 'Email': '[e-mail]'},               {'Reg': '2018-MC-03', 'Name': 'Ali Khan', 'Email': '[e-mail]'},               {'Reg': '2018-MC-04', 'Name': 'Abdullah Akram',                'Email': '[e-mail]'}]  # A List of Dictionariesmaxspace = len(max(allStudents, key=lambda x:len(x['Name']))['Name']) + 4 # add 4 spaces.for i in range(len(allStudents)):    listbox.insert(END, f"{allStudents[i]['Reg']}     {allStudents[i]['Name'].ljust(maxspace)}{allStudents[i]['Email']}")listbox.configure(yscrollcommand=scrollbar.set)scrollbar.configure(command=listbox.yview)mainloop()它显示：

Answer 2

您可以使用string formatting和固定/等宽字体：listbox = Listbox(students_Box, width=90, bg='azure', font='Courier 11') # use a fixed/monospaced font...for rec in allStudents:    listbox.insert(END, f"{rec['Reg']:15}{rec['Name']:30}{rec['Email']}")如果您不喜欢硬编码宽度，则可以计算每列的最大宽度：widths = {key:0 for key in allStudents[0]}for rec in allStudents:    for key in rec:        widths[key] = max(widths[key], len(rec[key]))for rec in allStudents:    listbox.insert(END, f"{rec['Reg']:{widths['Reg']}}  {rec['Name']:{widths['Name']}}  {rec['Email']}")

Answer 3

您可以尝试以下代码。您必须使用等宽字体才能使脚本正常工作from tkinter import *root = Tk()students_Box = LabelFrame(root,                    text = 'Registered Students', bd = 4,                    relief = GROOVE, labelanchor = 'n',                    font = 'Arial 10 bold', fg = 'navy blue',                    width = 850, height = 180)                            students_Box.grid_propagate(0)students_Box.pack(pady = 15)scrollbar = Scrollbar(students_Box)scrollbar.pack(side = RIGHT, fill = Y)listbox = Listbox(students_Box, width = 90, bg = 'azure', font = ('Consolas', 10, ''))#'TkDefaultFont 11')listbox.pack(padx = 5, pady = 10)allStudents = [{'Reg': '2018-MC-01', 'Name': 'Usman Khan', 'Email': '[e-mail]'},            {'Reg': '2018-MC-02', 'Name': 'Muhammad Ehtisham Zafar', 'Email': '[e-mail]'},            {'Reg': '2018-MC-03', 'Name': 'Ali Khan', 'Email': '[e-mail]'},            {'Reg': '2018-MC-04', 'Name': 'Abdullah Akram', 'Email': '[e-mail]'}]   # A List of DictionariesMaxRegLength = len(max(allStudents, key=lambda s: len(s['Reg']))['Reg'])MaxNameLength = len(max(allStudents, key=lambda s: len(s['Name']))['Name'])print(MaxRegLength, MaxNameLength)# MaxEmailLength = max(allStudents, key=lambda s: len(s['name']))for i in range(len(allStudents)):    listbox.insert(END,     '%s         %s          %s'%(allStudents[i]['Reg'].ljust(MaxRegLength), allStudents[i]['Name'].ljust(MaxNameLength), allStudents[i]['Email']))    # f"{allStudents[i]['Reg'].ljust(MaxRegLength)}       {allStudents[i]['Name'].ljust(MaxNameLength)}       {allStudents[i]['Email']}")listbox.configure(yscrollcommand = scrollbar.set)scrollbar.configure(command = listbox.yview)mainloop()