发展一个 for 循环以跳过不等于的字典键和值

Question

背景

我的结构如下：

trash = [ {'href': 'https://www.simplyrecipes.com/recipes/cuisine/portuguese/'},

          {'href': 'https://www.simplyrecipes.com/recipes/cuisine/german/'},

          {'href': 'https://www.simplyrecipes.com/recipes/season/seasonal_favorites_spring/'},

          {'href': 'https://www.simplyrecipes.com/recipes/type/condiment/'},

          {'href': 'https://www.simplyrecipes.com/recipes/ingredient/adobado/'}]

          {'href': 'https://www.simplyrecipes.com/', 

          'title': 'Simply Recipes Food and Cooking Blog', 'rel': ['home']},]

如您所见，大多数键是'href'，大多数值包含'https://www.simplyrecipes.com/recipes/'. 问题是那些不符合此命名约定的键和值......

代码：

此代码遍历结构并使用re.findall获取之间的字符串值'recipes/'，然后继续/为其对应的值创建一个新的键名。

for x in trash:

    for y in x.values():

        txt = ''

        for i in re.findall("recipes/.*", y):

            txt += i

            title = txt.split('/')[1]

            print({title: y})

输出：

假设我删除了不符合被命名和包含代码字符串值的命名约定的keys和，如下所示：values'href''https://www.simplyrecipes.com/recipes/'

{'cuisine': 'https://www.simplyrecipes.com/recipes/cuisine/portuguese/'}

{'cuisine': 'https://www.simplyrecipes.com/recipes/cuisine/german/'}

{'season': 'https://www.simplyrecipes.com/recipes/season/seasonal_favorites_spring/'}

{'type': 'https://www.simplyrecipes.com/recipes/type/condiment/'}

{'ingredient': 'https://www.simplyrecipes.com/recipes/ingredient/adobado/'}

问题：

代码的问题是，TypeError: expected string or bytes-like object如果结构的键和值不符合代码中的命名约定，我会得到一个。

问题：

我将如何改进这段代码，以便它跳过任何未命名的键'href'，如果它们被命名'href'，如果它们的值不包含，将跳过'https://www.simplyrecipes.com/recipes/'？

Answer 1

for d in trash:    for key, value in d.items():        if key != "href" or "https://www.simplyrecipes.com/recipes/" not in value:            continue  # Move onto next iteration        txt = ''        for i in re.findall("recipes/.*", value):            txt += i            title = txt.split('/')[1]            print({title: value})您可以使用 迭代字典的键和值dict.items()。然后你可以使用if语句来检查你的条件，continue如果他们不满足。