如何将 $p[ 1 ] 用传址方式 传给 $p[ 0 ]

Question

function test() {
$a = 1;
$b = 2;
testa( 'testb', $a );
echo $a, $b;
}

function testa() {
$p = func_get_args();
$fun = $p[ 0 ];
$p1 = & $p[ 1 ]; 
$fun( $p1 );
}

function testb( &$a, &$b ) {
$a = 'a';
$b = 'b';
}

test();

Answer 1

我依然不是太明白你的表达 ...如果你是想通过&nbsp;func_get_args()&nbsp;来获取一个参数变量的引用 ... 很遗憾 ... 你做不到 ...不过我们可以用一些替代方案来完成 ... 没细去琢磨 ... 第一时间能想到的方法类似下面这样 ...<?phpfunction&nbsp;test()&nbsp;{&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;make&nbsp;an&nbsp;object&nbsp;and&nbsp;forget&nbsp;about&nbsp;reference&nbsp;...&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;$sunyanzi&nbsp;=&nbsp;(object)[&nbsp;'a'&nbsp;=>&nbsp;1,&nbsp;'b'&nbsp;=>&nbsp;2&nbsp;];&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;just&nbsp;call&nbsp;the&nbsp;function&nbsp;...&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;func_caller(&nbsp;'callee',&nbsp;$sunyanzi&nbsp;);&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;is&nbsp;this&nbsp;the&nbsp;result&nbsp;you&nbsp;want&nbsp;..?&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;echo&nbsp;$sunyanzi->a,&nbsp;$sunyanzi->b;&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;done&nbsp;...&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;return; }function&nbsp;func_caller()&nbsp;{&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;you&nbsp;can&nbsp;not&nbsp;get&nbsp;reference&nbsp;via&nbsp;func_get_args()&nbsp;...&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;$args&nbsp;=&nbsp;func_get_args();&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;using&nbsp;the&nbsp;most&nbsp;normal&nbsp;way&nbsp;to&nbsp;call&nbsp;the&nbsp;function&nbsp;...&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;return&nbsp;$args[0](&nbsp;$args[1]&nbsp;); }function&nbsp;callee(&nbsp;$object&nbsp;)&nbsp;{&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;a&nbsp;different&nbsp;way&nbsp;to&nbsp;assign&nbsp;value&nbsp;...&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;$object->a&nbsp;=&nbsp;'a';&nbsp;&nbsp;&nbsp;&nbsp;$object->b&nbsp;=&nbsp;'b';&nbsp;&nbsp;&nbsp;&nbsp;/*&nbsp;actually&nbsp;i&nbsp;just&nbsp;replace&nbsp;"$"&nbsp;into&nbsp;"$object->"&nbsp;...&nbsp;*/ &nbsp;&nbsp;&nbsp;&nbsp;return; }/*&nbsp;here&nbsp;we&nbsp;go&nbsp;...&nbsp;*/test();不太喜欢你的代码风格所以小修改了一下 ... 但愿不会影响恩 ...这种方式虽然可以实现 ... 但是从架构的角度讲不是太好 ...因为在对象传递的过程中 ... 你无法取消这个引用 ... 所以尽量还是换一种程序结构吧 ...恩 ... 就是这样啦 ... 希望我没误会你的意思 ...