将变量从一个部分传递到另一个 PHP
我这里有这段代码。它的作用是：首先用户必须提交一个index.html表格，这样做意味着他必须用他的分数完成所有输入（例如 80/100 成绩）。之后用户按下提交按钮，如您所见，我必须//foreach statement在表格上显示他们的信息。这很好用。但今天我还添加了一个按钮，将此表格信息转换为 document.xls(Excel) . 很确定我在将 php 变量从一个部分传递到另一个 php 部分时做错了。此外，<table>必须介于两者之间<body> </body>，而不是像echo <table>我所说的那样，否则脚本无法正常工作。
基本上我想要正确的方法从第一个 php 部分获取变量$name $score1 $score2等并将它们放置到<td> <?php $name = $_SESSION['name']; ?>`` </td> <td> <?php $score = $_SESSION['score']; ?> </td> 所以这是我的代码：
<?php session_start();?>
<html>
<head>
</head>
</html>
<body>
<?php
function average(){
$name = $_POST['name'];
$score1 = $_POST['math'];
$score2 = $_POST['chemistry'];
$score3 = $_POST['history'];
$score4 = $_POST['english'];
$score5 = $_POST['language'];
$score6 = $_POST['religious'];
$score7 = $_POST['german'];
$score8 = $_POST['physics'];
$score9 = $_POST['latin'];
$score10 = $_POST['french'];
$score11 = $_POST['music'];
$study = array(
"Mathimatics"=> $score1,
"Chemistry"=> $score2,
"Histroy"=> $score3,
"English"=> $score4,
"Language"=> $score5,
"Religious"=> $score6,
"German"=> $score7,
"Physics"=> $score8,
"Latin"=> $score9,
"French"=> $score10,
"Music"=> $score11
);
$_SESSION['name'] = $name;
$_SESSION['score1'] = $score1;
//echo "<div>";
//echo "<table class=\'tableToExl\'>";
//echo " <th>Projects</th>";
//echo " <th>Score</th>";
//foreach ($study as $key=>$values){
//echo " <tr>";
//echo " <td>$key</td>";
//echo " <td>$values</td>";
//echo " </tr>";
//}
}
average();
?>
<table class="tableToExl" data-tableName="Test Table 1">
<th>Projects</th>
<th>Score</th>
<tr>
<!-- For example i placed only the name of the student and the first Project-->
<td> <?php $name = $_SESSION['name']; ?> </td>
<td> <?php $score = $_SESSION['score']; ?> </td>
</tr>
</table>
任何建议我做错了什么？谢谢
UYOU1回答
-
精慕HU
尝试：<td> <?php echo $_SESSION['name']; ?> </td> <td> <?php echo $_SESSION['score']; ?> </td>
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