如果键相同而不使用嵌套循环，则多维数组合并为一个数组
[
{
"status": true,
"data": [
{
"id": 2,
"name": "Algeria",
"country_code": "DZ",
"regions": [
{
"id": 2,
"country_id": 2,
"region_code": "RG01",
"depots": [
{
"id": 5,
"region_id": 2,
"depot_code": "DP04",
"depot_name": "North Depot",
"area": [
{
"id": 1,
"depot_id": 5,
"area_code": "AR1",
"area_name": "Area-1"
},
{
"id": 2,
"depot_id": 5,
"area_code": "AR2",
"area_name": "Area-2"
}
]
},
{
"id": 6,
"region_id": 2,
"depot_code": "DP06",
"depot_name": "east Depot",
"area": [
{
"id": 3,
"depot_id": 6,
"area_code": "AR3",
"area_name": "Area-3"
}
]
}
]
},
{
"id": 3,
"country_id": 2,
"region_code": "RG02",
"depots": []
}
]
}
]
}
]
我想将区域合并到单个数组中
"area": [
{
"id": 1,
"depot_id": 5,
"area_code": "AR1",
"area_name": "Area-1"
},
我不想使用多个 foreach。提前致谢。
陪伴而非守候2回答
-
qq_笑_17
您可以使用以下代码递归迭代所有结构并仅提取您需要的数据（按键）。我假设 $data 具有您的原始数据结构，并且在 $result 中您将获得区域数组：$it = new RecursiveIteratorIterator(new RecursiveArrayIterator($data), RecursiveIteratorIterator::SELF_FIRST);$result = [];foreach ($it as $k => $v) { if ($k === 'area') { $result = array_merge($result, $v); }} -
元芳怎么了
我不会使事情过于复杂，遍历您的数据结构。将所有区域添加到集合中。准备您的数据结构，我添加了一个检查以确保没有重复项unique()。$data = 'your-data';$areas = collect();foreach($data->data as $country) { foreach($country->regions as $region) { foreach ($region->depots as $depot) { $areas->concat($depot->area); } } }$result = ['area' => $areas->unique('id')->all()];
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