如图，关于数组拆分合并优化的问题，该怎么解决？

explode使用一个字符串分割另一个字符串$str = "11,22,33";$arr = explode(",",$str);print_r($arr);Array([0] => 11[1] => 22[2] => 33)12345678910implode将一个一维数组的值转化为字符串$arr = [11,22,33];$str = implode("#",$arr);echo $str;11#22#3312345split用正则表达式将字符串分割到数组中preg_split()函数使用了Perl兼容正则表达式语法，通常是比split()更快的替代方案。如果不需要正则表达式的威力，则使用explode()更快，这样就不会招致正则表达式引擎的浪费。该函数在PHP7中已被废弃$str = "123dqaw76eqwv8902fwer12356";$arr = split("[a-z]+", $str);print_r($arr);Array([0] => 123[1] => 76[2] => 8902[3] => 12356)1234567891011preg_split通过一个正则表达式分隔字符串如果你不需要正则表达式功能，可以有更快(并且更简单)的选择比如 explode() 或 str_split()。如果没有成功匹配，将会返回一个数组，包含了单个元素，即输入的字符串。$str = "123dqaw76eqwv8902fwer12356";$arr = preg_split("/[a-z]+/i", $str);print_r($arr);Array([0] => 123[1] => 76[2] => 8902[3] => 12356)1234567891011str_split将字符串转换为数组$str = "hello world";print_r(str_split($str));print_r(str_split($str, 3));Array([0] => h[1] => e[2] => l[3] => l[4] => o[5] =>[6] => w[7] => o[8] => r[9] => l[10] => d)Array([0] => hel[1] => lo[2] => wor[3] => ld)12345678910111213141516171819202122232425array_chunk将一个数组分割成多个$input_array = array('a', 'b', 'c', 'd', 'e');print_r(array_chunk($input_array, 2));print_r(array_chunk($input_array, 2, true));Array([0] => Array([0] => a[1] => b)[1] => Array([0] => c[1] => d)[2] => Array([0] => e))Array([0] => Array([0] => a[1] => b)[1] => Array([2] => c[3] => d)[2] => Array([4] => e))1234567891011121314151617181920212223242526272829303132333435363738394041424344array_combine创建一个数组，用一个数组的值作为其键名，另一个数组的值作为其值$a = array('green', 'red', 'yellow');$b = array('avocado', 'apple', 'banana');$c = array_combine($a, $b);print_r($c);Array([green] => avocado[red] => apple[yellow] => banana)1234567891011array_merge合并一个或多个数组。一个数组中的值附加在前一个数组的后面，返回作为结果的数组。别忘了数字键名将会被重新编号！$array1 = array("color" => "red", 2, 4);$array2 = array("a", "b", "color" => "green", "shape" => "trapezoid", 4);$result = array_merge($array1, $array2);print_r($result);Array([color] => red[0] => 2[1] => 4)Array([0] => a[1] => b[color] => green[shape] => trapezoid[2] => 4)Array([color] => green[0] => 2[1] => 4[2] => a[3] => b[shape] => trapezoid[4] => 4)1234567891011121314151617181920212223242526272829如果你想完全保留原有数组并只想新的数组附加到后面，用 + 运算符。如果两个被合并的数组含有相同的key，则保留第一个，忽略后边的。$array1 = array(0 => 'zero_a', 2 => 'two_a', 3 => 'three_a');$array2 = array(1 => 'one_b', 3 => 'three_b', 4 => 'four_b');$result = $array1 + $array2;print_r($result);Array([0] => zero_a[2] => two_a[3] => three_a[1] => one_b[4] => four_b)12345678910111213array_merge_recursive递归地合并一个或多个数组如果输入的数组中有相同的字符串键名，则这些值会被合并到一个数组中去，这将递归下去，因此如果一个值本身是一个数组，本函数将按照相应的条目把它合并为另一个数组。然而，如果数组具有相同的数组键名，后一个值将不会覆盖原来的值，而是附加到后面。$ar1 = array("color" => array("favorite" => "red"), 5);$ar2 = array(10, "color" => array("favorite" => "green", "blue"));$result = array_merge_recursive($ar1, $ar2);print_r($ar1);print_r($ar2);print_r($result);Array([color] => Array([favorite] => red)[0] => 5)Array([0] => 10[color] => Array([favorite] => green[0] => blue))Array([color] => Array([favorite] => Array([0] => red[1] => green)[0] => blue)[0] => 5[1] => 10)123456789101112131415161718192021222324252627282930313233343536373839404142compact建立一个数组，包括变量名和它们的值对每个参数，compact() 在当前的符号表中查找该变量名并将它添加到输出的数组中，变量名成为键名而变量的内容成为该键的值。任何没有变量名与之对应的字符串都被略过。$city  = "San Francisco";$state = "CA";$event = "SIGGRAPH";$location_vars = array("city", "state");$result = compact("event", "nothing_here", $location_vars);print_r($result);Array([event] => SIGGRAPH[city] => San Francisco[state] => CA)12345678910111213extract从数组中将变量导入到当前的符号表检查每个键名看是否可以作为一个合法的变量名，同时也检查和符号表中已有的变量名的冲突。返回成功导入到符号表中的变量数目。$var_array = [    "color" => "blue",    "size"  => "medium",    "shape" => "sphere"];extract($var_array);echo "$color, $size, $shape\n";

如图，关于数组拆分合并优化的问题，该怎么解决？

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