在已经从页面接收数据后使用 PHP 将数据发送到另一个页面
我想做的是：在将数据从 form.php 发送到 data_received.php 之后，我希望 data_received.php 将其发送到 pdf.php，而无需用户填写另一个表格。那可能吗？
这是东西
form.php 的表单示例
<form action="data_received.php" method="post">
<div data-for="date">
<label>Date</label>
<input type="text" name="date">
</div>
<div data-for="time">
<label>Time</label>
<input type="text" name="time">
</div>
data_received.php：
<?php
$date = $_POST['date'];
$time = $_POST['time'];
echo '$date';
echo '$time';
?>
<button onclick="window.location.href = 'pdf.php';">Print to pdf </button>
<button onclick="windoe.location.href = 'form.php';>Back</button>
我只想知道如何让用户对 pdf.php 的 $date 和 $time 的回答
婷婷同学_浏览 113回答 2
2回答
-
隔江千里
解决方案在这里！表单.php<html><head> <title>Log-in</title> <link rel="stylesheet" type="text/css" href="style.css"></head><body><div class="header"> <h1>Log-in</h1></div><form action="data_received.php" method="post"><div data-for="date"> <label>Date</label> <input type="text" name="date"> </div><div data-for="time"> <label>Time</label> <input type="text" name="time"> </div> <input type="submit" name="register_btn" class="Register"></td></body></html> data_received.php<html><head> <title>Log-in</title> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script> <script> $(window).on('load', function() { window.open("pdf.php", "pdf", "height=400,width=400"); }) </script></head><body><div class="header"> <h1>Log-in</h1></div><form > <?phpsession_start();$date = $_POST['date'];$time = $_POST['time'];$_SESSION["date"] = $_POST['date'];$_SESSION["time"] = $_POST['time'];echo $date;echo '<br/>';echo $time;?><br/><input type="Button" value="Back" onclick="windoe.location.href ='form.php';"><input type="Button" value="Print to pdf " onclick="window.location.href = 'pdf.php';"></form></body></html> pdf文件<html><head> <title>Log-in</title> <link rel="stylesheet" type="text/css" href="style.css"></head><body><div class="header"> <h1>PDF</h1></div><form method="post" > <?php session_start(); ?> <table> <tr> <td>Date:</td> <td><input type="text" value="<?PHP if(isset($_SESSION['date'])){echo $_SESSION['date'];}?>"></td> </tr> <tr> <td>Time:</td> <td><input type="text" value="<?PHP if(isset($_SESSION['time'])){echo $_SESSION['time'];}?>"></td> </tr> <tr> <td></td> <td><input type="Button" value="Close" onclick="self.close();"> </td> </tr> </table></form></body></html> -
尚方宝剑之说
解决方案在这里！针对你的疑惑，我已经计划好了，希望对你有用。
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