口译员在尝试进行列表理解时说缩进/空格使用不一致

Question

def skip_elements(elements) :

    new_list = []

    for i in elements :

        if i % 2 == 0 :

            new_list= new_list.append(i)

            i+=1

        else :

             i+=1

    return new_list

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']

print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']

print(skip_elements([])) # Should be []

Answer 1

if i % 2 == 0 :    new_list= new_list.append(i)    i+=1else :     i+=1    ^ extra space - you might want to use tabs instead of spaces when it comes to python - or any language for that matternew_list = new_list.append(i).append()会回来的None。将其替换为：new_list.append(i)最后，要返回一个包含所有奇数元素的列表需要付出很多努力。你可以简单地做（感谢@chepner）：def skip_elements(elements):    return elements[::2]