Python 字符串操作——拆分、切片、从 HEX 转换为 DEC

我有以下字符串:


s = "0015CB,0,0,01,006D,0016CF1,4,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00F4E7D,1,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0008184,8,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA704,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0014EC8,2,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FAEEA,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FADE9,5,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA5A5,3,000D"

Selcuk 好心地协助在每次迭代时将其拆分,000D因此提取的第一个值是0016CF1,4


现在我需要帮助将这个值的第一部分从十六进制转换为十进制,并将逗号后面的数字保留原样。所以它会是93425,4或93425 4


到目前为止我有以下内容并且它有效,但不是很优雅,请一些人帮助提高效率/清洁度。谢谢。


my_list = [e[-9:] for e in s.split(",000D")]

print(my_list)


# Output = ['0016CF1,4', '00F4E7D,1', '0008184,8', '00FA704,9', '0014EC8,2', '00FAEEA,9', '00FADE9,5', '00FA5A5,3', '']



# for testing print the first value from the list [0]

# output = 0016CF1,4


print(my_list[0])


# save my_list in a string called list and remove the comma and check digit

# output = 0016CF1


list=str(my_list)

result = [e[-7:] for e in list.split(",")]

print(result[0])


# convert the first value from HEX to DEC

# output= 93425


res1 = int(result[0],16)

print(res1)


#  get the checkdigit for the first value in the list

checkdigit = [f[-1:] for f in s.split(",000D")]

print(checkdigit[0])


# output = 4


#  join res1 and checkdigit


print(res1,checkdigit[0])


# output = 93425 4

理想情况下,我希望在循环中使用上面的内容,以便原始列表中的所有值都像示例中的第一个值一样进行转换。谢谢


月关宝盒
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1回答

梦里花落0921

这是一个非常紧凑的解决方案:my_list = ['0016CF1,4', '00F4E7D,1', '0008184,8', '00FA704,9',           '0014EC8,2', '00FAEEA,9', '00FADE9,5', '00FA5A5,3']result = [f'{int(x[:-2], 16)} {x[-1]}' for x in my_list]以下是最终内容result:['93425 4', '1003133 1', '33156 8', '1025796 9', '85704 2', '1027818 9', '1027561 5', '1025445 3']
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