我有以下字符串:
s = "0015CB,0,0,01,006D,0016CF1,4,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00F4E7D,1,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0008184,8,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA704,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,0014EC8,2,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FAEEA,9,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FADE9,5,000D,01,0202,01,0E09,01,02,00,006D,0000,0,0,01,006D,00FA5A5,3,000D"
Selcuk 好心地协助在每次迭代时将其拆分,000D因此提取的第一个值是0016CF1,4
现在我需要帮助将这个值的第一部分从十六进制转换为十进制,并将逗号后面的数字保留原样。所以它会是93425,4或93425 4
到目前为止我有以下内容并且它有效,但不是很优雅,请一些人帮助提高效率/清洁度。谢谢。
my_list = [e[-9:] for e in s.split(",000D")]
print(my_list)
# Output = ['0016CF1,4', '00F4E7D,1', '0008184,8', '00FA704,9', '0014EC8,2', '00FAEEA,9', '00FADE9,5', '00FA5A5,3', '']
# for testing print the first value from the list [0]
# output = 0016CF1,4
print(my_list[0])
# save my_list in a string called list and remove the comma and check digit
# output = 0016CF1
list=str(my_list)
result = [e[-7:] for e in list.split(",")]
print(result[0])
# convert the first value from HEX to DEC
# output= 93425
res1 = int(result[0],16)
print(res1)
# get the checkdigit for the first value in the list
checkdigit = [f[-1:] for f in s.split(",000D")]
print(checkdigit[0])
# output = 4
# join res1 and checkdigit
print(res1,checkdigit[0])
# output = 93425 4
理想情况下,我希望在循环中使用上面的内容,以便原始列表中的所有值都像示例中的第一个值一样进行转换。谢谢
梦里花落0921
相关分类