如何在包含占位符的字典中加载 yaml 文件内容？

Question

输入yaml文件

kind: Testing

metadata:

   name: test-file

   annotations:

      purpose: To test the deployed code

spec:

   containers:

     - name: client

       image: {{.registry}}/xyz:{{.client}}

       env:

         {{ if ne .proxy ""  }}

         - name: http_proxy

         value: "{{.proxy}}"

         {{ end -}}

我想加载字典中除占位符内容之外的所有 yaml 内容。我怎样才能实现它？我可以使用任何正则表达式来过滤占位符吗？

我尝试使用以下代码，它适用于没有占位符值但在上述 yaml 中给出解析错误的 yaml。

def __load_yaml(filename):

  with open(filename, 'r') as stream:

    try:

        return yaml.load(stream, Loader=yaml.FullLoader)

    except yaml.YAMLError as exception:

        raise exception

 

 def main():

   data = {}

   data.update(__load_yaml(file))

   print(data)

 if __name__ == '__main__':

   main()

我也试过这个，它正在将 yaml 加载到字典中，但也给出了 FileNotFoundError。有没有办法将列表读取为流？或任何建议我怎样才能实现它？：

def __load_yaml(filename):

with open(filename, 'r') as stream:

    try:

        data = []

        for text in stream:

            match = re.search(r'\{\{.*?\}\}', text)

            if not match and text != None:

                data.append(text)

        with open(str(data), 'r') as stream:

            return yaml.load(stream, Loader=yaml.FullLoader)

    except yaml.YAMLError as exception:

        raise exception

Answer 1

def __load_yaml(filename):  with open(filename, "r") as stream:    string = stream.read()    # Find placeholders    reg_one = re.findall(r':\{\{.*?\}\}', string)    reg_two = re.findall(r'\{\{.*?\}\}', string)    placeholders = reg_one + reg_two    # Replace placeholders    for placeholder in placeholders:        string = string.replace(placeholder, "")    try:        return yaml.load(string, Loader=yaml.FullLoader)    except yaml.YAMLError as exception:        raise exception