有没有办法将字符串转换为 discord.py 中的 discord.Member 类型？

Question

我一直在尝试向我的 discord 机器人添加一个井字游戏迷你游戏。我最初在 @client.command() 中编写代码，因为我认为您可以在其中使用 client.wait_for() 但不幸的是，您不能。无论如何，我不得不将我的代码转换为在 on_message() 函数上工作，现在我遇到了从初始命令中获取 discord.Member 变量类型的问题，比如 ~tictactoe @user#1234。因此，例如，我尝试在 on_message() 函数中编写此代码但没有成功。

if message.content.startswith("~tictactoe") or message.content.startwith("~ttt"):

    member = str(message).split(" ")

    member = discord.Member(member[1])

    channel = message.channel

这是我的完整代码：

if message.content.startswith("~tictactoe") or message.content.startwith("~ttt"):

    member = str(message).split(" ")

    member = discord.Member(member[1])

    channel = message.channel

    if member.bot: channel.send("You can't play against a bot!")

    else:

        while True:

            x = 0

            player = [message.author if (x % 2 == 0) else member]

            x += 1

            symbol = [':x:' if player == message.author else ':o:']

            def check(m):

                possibilities = ['a1','a2','a3','b1','b2','b3','c1','c2','c3']

                return (m.content.lower() in possibilities or m.content.lower() == 'end') and m.author == player and m.channel == channel

            if x != 1:

                channel.send("TicTacToe\n{message.author.name} vs. {member.name}")

                for i in range(3):

                    channel.send(f"{board[i][0]}{board[i][1]}{board[i][2]}\n")

            channel.send(f"{player.mention}, where do you want to place your marker?\na1\ta2\ta3\nb1\tb2\tb3\nc1\tc2\tc3\n or `end` to end game")

            try:

                cell = await client.wait_for('message', timeout=20.0, check=check)

            except:

                channel.send("Input invalid or you took too long to respond.")

任何帮助appreciated :)

Answer 1

使用message.mentionsmessage.mentionsdiscord.Member返回提到的列表（或者discord.User如果消息是在私人消息中发送的）。# Safe methodif message.mentions:    member = message.mentions[0]else:    return  # There was no mentions# Riskier but simpler method# Having no mentions or more than one would raise an errormember, = message.mentions快速说明：回复被视为提及，message.mentions将包含您的消息中提到的成员和您回复的成员。解析消息提及等同于<@!id>，因此您可以解析您的消息以获取成员的 id：command, member = message.split()member_id = int(member.strip('<@!>'))然后，要从discord.Member中取出对象：# Regardless of cache, but sends an API callmember = await bot.fetch_member(member_id)# Depends on the bot's cache# Doesn't make any API calls and isn't asynchronousmember = message.guild.get_member(member_id)