在带有对象的嵌套数组中过滤
我有一个包含三个书籍对象的数组。每个书籍对象都有一个 bookIds 数组。我想以快速有效的方式按 bookId (3,1) 进行过滤，因为我的数组将来会很容易增长。我尝试使用 map，但即使使用 deepCopy 也会更改我的原始数组！有没有办法在不使用递归的情况下使用过滤器函数？
this.booksList =
[
{
"books": [
{
"bookId": 3
},
{
"bookId": 2
}
],
"id": 1,
"name": "Name 1",
"description": "desc 1"
},
{
"books": [
{
"bookId": 5
},
{
"bookId": 2
}
],
"id": 2,
"name": "Name 2",
"description": "desc 2"
},
{
"books": [
{
"bookId": 1
},
{
"bookId": 3
}
],
"id": 3,
"name": "Name 3",
"description": "desc 3"
}
]
地图方法：
let results = this.books.map(function (book) {
book.books = book.books.filter(x => x.bookId == 1 || x.bookId == 3);
return book;
}).filter(({ books }) => books.length);
地图结果：不是预期的结果！
[
{
"books": [
{
"bookId": 3
}
],
"id": 1,
"name": "Name 1",
"description": "desc 1"
},
{
"books": [
{
"bookId": 1
},
{
"bookId": 3
}
],
"id": 3,
"name": "Name 3",
"description": "desc 3"
}
]
预期成绩 ：
[
{
"books": [
{
"bookId": 3
},
{
"bookId": 2
}
],
"id": 1,
"name": "Name 1",
"description": "desc 1"
},
{
"books": [
{
"bookId": 1
},
{
"bookId": 3
}
],
"id": 3,
"name": "Name 3",
"description": "desc 3"
}
]
谢谢，
喵喔喔2回答
-
MMTTMM
我想你正在寻找filter并且some-const input = [{books:[{bookId:3},{bookId:2}],id:1,name:"Name 1",description:"desc 1"},{books:[{bookId:5},{bookId:2}],id:2,name:"Name 2",description:"desc 2"},{books:[{bookId:1},{bookId:3}],id:3,name:"Name 3",description:"desc 3"}]const query = [3, 1]const result = input.filter(({ books = [] }) => books.some(({ bookId = null }) => query.includes(bookId)) )console.log(JSON.stringify(result, null, 2))输出 -[ { "books": [ { "bookId": 3 }, { "bookId": 2 } ], "id": 1, "name": "Name 1", "description": "desc 1" }, { "books": [ { "bookId": 1 }, { "bookId": 3 } ], "id": 3, "name": "Name 3", "description": "desc 3" }] -
呼如林
const booksList=[ {books:[{bookId:3},{bookId:2}],id:1,name:"Name 1",description:"desc 1"}, {books:[{bookId:5},{bookId:2}],id:2,name:"Name 2",description:"desc 2"}, {books:[{bookId:1},{bookId:3}],id:3,name:"Name 3",description:"desc 3"},];const byBookIDs = (...IDs) => booksList.filter(b => b.books.some(b => IDs.includes(b.bookId)));console.log(byBookIDs(1, 3));MDN 数组过滤器- 返回一个子集MDN Array Some - 尽快匹配（并返回）一些MDN Array Includes - 在数组中查找项目
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JavaScript