从数组中取出随机字符串，将其放入新数组中，然后再将其放回旧数组中

Question

我正在尝试造一个从数组中随机选择项目两次的句子。第一个选择的项目暂时从数组中删除，因此不能再次选择，然后第二个项目也被随机选择并添加到句子中。然后，为了重置它以便稍后可以再次执行此操作，我尝试将第一个选择的项目添加回其初始数组。

问题是，当我这样做时，chosenWord1 在句子中显示为我希望的字符串，但 chosenWord2 显示的是索引号。

array = ["word","another word", "yet another word"];

/* put a random word from the array in its own value and then 

remove it from the array so it can't be chosen in next step */

let chosenWord1 = array.splice(Math.random() * array.length, 1)[0];

/* pick another random word from the same, altered array */

let chosenWord2 = Math.floor(Math.random() * array.length);

/* a function that puts a sentence on the webpage concatenating the strings 

from chosenWord1 and chosenWord2 goes here. then... */

/* add back the previously removed word so this process can repeat again 

with the same items in the array as there was before anything was done to it */

array.splice(1,0,chosenWord1);

另外，如果有一些更明智的方法可以构建它，请告诉我。我对此还是很陌生。

Answer 1

我不知道这是否是您需要的，但这会重复提取两个随机单词，而不是将它们从原始数组中取出。for 循环用于显示它如何处理不同的单词。const array = ["word", "another word", "yet another word"];const randomNumber = (key) => Math.floor(Math.random() * key);for (let i = 0; i < 10; i++) {&nbsp; const { [randomNumber(array.length)]: wordOne, ...rest } = array;&nbsp; const { [randomNumber(array.length - 1)]: wordTwo } = Object.values(rest);&nbsp; console.log(`${wordOne} and ${wordTwo}`);}