请问我该将函数作为参数传递给函数啊？

Question

#include <iostream>
#include <cstring>
using namespace std;
int * count (const char * const s)
{ 
int *count = new int [10]; 
for(int j = 0;j < 10;j++) 
{  
count[j] = 0;  
for (int k = 0;k < strlen(s);k++)  
{ if (s[k]-48 == j)  
{  
count[j]++;  
}  
} 
}
return count;
delete [] count;
}
int main()
{ 
int * counts = count("0000"); 
for (int k = 0;k < 10;k++) 
{ 
cout << counts[k] << " "; 
}
return 0;
}

上面这段代码中包含
int * count (const char * const s)
重新设计函数，讲统计结果数组作为参数COUNTS传递给函数
void count(const char * const s,int * counts,int size)

Answer 1

void count(const char* s, int* cnts,int size){int i;memset(cnts,0,sizeof(int)*10);for (i=0;i<size;i++){if (s[i] >= '0' && s[i]<= '9'){cnts[s[i]-'0']++;}}}这样就可以了

Answer 2

void count( __in const char * const s,__out int * counts,__in int size) //size是const的大小{for(int j = 0;j < 10;j++)&nbsp;{&nbsp;&nbsp;counts[j] = 0;&nbsp;&nbsp;for (int k = 0;k < size;k++)&nbsp;&nbsp;{&nbsp;if (s[k]-48 == j) counts[j]++;}&nbsp;}}