结果执行到这出错，请问什么问题啊？我该怎么修改

Question

#include <stdio.h> #include <string.h> int main(void) { char *name[]={ "Illegal day", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"}; printf("hos = %s \n", name[0]); printf("hos = %s \n", name[1]); printf("hos = %s \n", name[3]); strncpy(name[0],"Illegal",7); printf("host = %s \n", name[0]); printf("host = %s \n", name[1]); printf("host = %s \n", name[3]); } [root@localhost 99]# ./test hos = Illegal day hos = Monday hos = Wednesday Segmentation fault ==》

Answer 1

你用char*name[]={"1...","2...","3...","4...","5...","6...","7...","8..."}的格式定义的name是个指针数组，其每一个元素都是一个char型指针，抽出第一个来看就是char*name[0]="1..."，它的一般形式是char*p="abc..."。这种形式定义的指针是所谓“常指针”，p指向的内容*p是不允许写改变的！而你的strncpy(name[0],"Illegal",7)试图把Illegal的前7位写进name[0]指向的单元开始的空间去，是非法的，所以报错！用strcpy(name[0],"Illegal")同样是不行的。name[0]~name[7]都是常指针，都不能被strcpy()操作。改进的办法是：将char*name[]改为charname[][12]={"...","...",...}，让name成为一个可以写操作的二维数组名就可以了。其中[12]是最长字符串Illegalday所需要的空间。