用所有数字替换每个元音以找到加密代码

Question

所以我必须替换名称列表中的每个元音以匹配加密代码，所以我需要的是，例如，对于“Andre”，我需要得到：0ndr0、0ndr1、0ndr2、0ndr3 ... 1ndr1， 1ndr2 ... 9ndr5 ... 9ndr9

这是我所做的简化版本：

def testVoyellePrenom():

    voyelle = ["A", "E", "I", "O", "U", "Y"]

    myNumbers = [a + 1 for a in range(-1,9)]

    myNumbers.reverse()

    pre = "ANDRE"

    testing = ""

    for x in pre:

        if(x in voyelle):

            for nb in myNumbers:

                pre = pre.replace(x,str(nb))

                x = str(nb)

                testing = pre

                print(testing)

Output :

9NDRE

8NDRE

7NDRE

6NDRE

5NDRE

4NDRE

3NDRE

2NDRE

1NDRE

0NDRE

0NDR9

0NDR8

0NDR7

0NDR6

0NDR5

0NDR4

0NDR3

0NDR2

0NDR1

0NDR0

Expected output :

...

0NDR0

1NDR9

1NDR8

1NDR7

1NDR6

1NDR5

1NDR4

1NDR3

1NDR2

1NDR1

1NDR0

....

Answer 1

这是一个解决方案。基本逻辑是：识别元音 ( vowel_inx) 的所有位置。为这些位置创建所有数字组合的叉积。循环这个叉积，并通过将数字分配到它们在原始术语中的相应位置来创建新词。    vowels = ["A", "E", "I", "O", "U", "Y"]    pre = "ANDRE"    import itertools    vowel_inx = [i for i in range(len(pre)) if pre[i] in vowels ]        ranges = [range(10) for _ in vowel_inx]    for comb in itertools.product(*ranges):        pw = list(pre)        for i in range(len(vowel_inx)):            pw[vowel_inx[i]] = str(comb[i])        print ("".join(pw))输出是：0NDR00NDR10NDR20NDR30NDR40NDR50NDR60NDR70NDR80NDR91NDR01NDR11NDR2... 

Answer 2

这是一个正确的方法：voyelle = ["A", "E", "I", "O", "U", "Y"]def permute_single_index(word, index):    permutations = []    word_left = word[0:index]    word_right = word[index+1:]    for i in reversed(range(10)):        permutations.append(f"{word_left}{i}{word_right}")    return permutationsdef testVoyellePrenom(pre):    upper_pre = pre.upper()    replace_indexes = [i for i, x in enumerate(upper_pre) if x in voyelle]    permutations = [upper_pre]    for ri in replace_indexes:        new_permutations = []        for word in permutations:            new_permutations += permute_single_index(word, ri)        permutations += new_permutations    print(permutations)    print(len(permutations))def main():    testVoyellePrenom("Andre")if __name__ == "__main__":    main()你最终得到 121 个排列。